Answer:
endurance length is 236.64 MPa
Explanation:
data given:
d = 37.5 mm
Sut = 760MPa
endurance limit is
Se = 0.5 Sut
= 0.5*760 = 380 MPa
surface factor is
Ka = a*Sut^b
where
Sut is ultimate strength
for AISI 1040 STEEL
a = 4.51, b = -0.265
Ka = 4.51*380^{-0.265}
Ka = 0.93
size factor is given as
Kb =1.29 d^{-0.17}
Kb = 0.669
Se = Sut *Ka*Kb
= 380*0.669*0.93
Se = 236.64 MPa
therefore endurance length is 236.64 MPa
Answer:
Explanation:
Sum of the side slope = 2 + 1 = 3
Length of first slope = 2/3 X 3.6 = 2 X 1.2 = 2.4m
Lenght of second slope = 1/3 X 3.6 = 1.2m
Area of the trapezoidal channel = (2.4 + 1.2)/2 X 3.6 = 1.8 X 3.6 = 6.48m²
Alternate dept = 50m³/6.48m²= 7.716m
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Answer:
Q=q
also
q=it
Explanation:
How to find magnitude of net electric charge when current flows through a capacitor with initial charge?
A capacitor is a device used in storing electric charges. The unit of capacitance is measured in farad
To find the magnitude of net electric charge in a capacitor, we use the following relation
Q=q
Q=the magnitude of net electric charge in coulombs
t=the time for an electron tpo pass through the capacitor
R=the resistance of the capacitor , measured in ohms
C=the capacitance of the capacitor measures in Farad
q=initial quantity of charge
Having all the parameters above will make it possible to determine the net electric charge
Recall also that
q=it
quantity (coulombs)=current*time(s)