Answer:
The speed at point B is 5.33 m/s
The normal force at point B is 694 N
Explanation:
The length of the spring when the collar is in point A is equal to:
The length in point B is:
lB=0.2+0.2=0.4 m
The equation of conservation of energy is:
(eq. 1)
Where in point A: Tc = 1/2 mcVA^2, Ts=0, Vc=mcghA, Vs=1/2k(lA-lul)^2
in point B: Ts=0, Vc=0, Tc = 1/2 mcVB^2, Vs=1/2k(lB-lul)^2
Replacing in eq. 1:
Replacing values and clearing vB:
vB = 5.33 m/s
The balance forces acting in point B is:
Fc-NB-Fs=0
Replacing values and clearing NB:
NB = 694 N
Answer:
13177.34 J
Explanation:
Work done = force × distance
work done by the engine = kinetic energy + potential energy + work done friction
kinetic energy due to the car's speed = 1/2mv² = 4468.5 J
potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J
work done by friction = 2870 J
work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J
Answer:
(a) The velocity of the exhaust gases. is 832.7 m/s
(b) The rate of fuel consumption is 0.6243 kg/s
Explanation:
For the given turbojet engine operating on an ideal cycle, the pressure ,temperature, velocity, and specific enthalpy of air at 
state are 
, 
, 
, and 
, respectively.
Use "ideal-gas specific heats of various common gases" to find the properties of air at room temperature.
Specific heat at constant pressure, 
= 1.005 kJ/kg.K
Specific heat ratio, k = 1.4
The net resultant direct force and angle on the vane is created when the water jet exits the vane at position 2 with 92% of its initial velocity.
<h3>What is mean by velocity?</h3>
- The speed at which a body or object is moving determines its direction of motion. A scalar quantity, speed is primarily. As a matter of fact, velocity is a vector quantity.
- The rate at which distance changes is what it is. It measures the displacement's rate of change. A body's velocity is defined as its speed in a particular direction.
- Velocity is a measure of how quickly a distance changes in relation to time. Having both magnitude and direction, velocity is a vector quantity.
- The rate of change in a body's displacement with respect to time is referred to as velocity. In the SI, m/s is its unit.
Given,
External angle of Curved Vane = 158°
mean velocity at 1 = 12 m/s
Volumetric flow rate = 
mean velocity at 
i) Force exerted in x - friction A C 1 = Volume
![F_{S_x} &=\rho A C_1\left[C_2 \cos \theta-C_1\right] \\](https://tex.z-dn.net/?f=F_%7BS_x%7D%20%26%3D%5Crho%20A%20C_1%5Cleft%5BC_2%20%5Ccos%20%5Ctheta-C_1%5Cright%5D%20%5C%5C)
![&=1000 \times \frac{55}{3600}\left[\left(11.04 \cos 158^{\circ}\right)-12\right]](https://tex.z-dn.net/?f=%26%3D1000%20%5Ctimes%20%5Cfrac%7B55%7D%7B3600%7D%5Cleft%5B%5Cleft%2811.04%20%5Ccos%20158%5E%7B%5Ccirc%7D%5Cright%29-12%5Cright%5D)
i![\rangle F_{\text {sc }}=\supseteq A c_1\left[C_2 \sin \theta\right] \\](https://tex.z-dn.net/?f=%5Crangle%20F_%7B%5Ctext%20%7Bsc%20%7D%7D%3D%5Csupseteq%20A%20c_1%5Cleft%5BC_2%20%5Csin%20%5Ctheta%5Cright%5D%20%5C%5C)
The complete question is:
A horizontal jet of water strikes a curved vane as shown in Figure C.1. The external angle of the curved vane is 158°.The mean velocity and volumetric flow rate of the water jet at position 1 are 12 m/s and 55 m³/h respectively. Due to friction, the water jet leaves the vane at position 2 with 92 % its original velocity.
(i) Direct force exerted by the water jet on the vane in the x - direction.
(ii) Direct force exerted by the water jet on the vane in the y - direction.
(ii) Net resultant direct force and angle on the vane.
To learn more about velocity, refer to:
brainly.com/question/24681896
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