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Monica [59]
3 years ago
7

What condition is necessary for an object to make a good reference point?

Physics
1 answer:
777dan777 [17]3 years ago
8 0
The object is fixed relative to the motion you are trying to describe.
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which principles of training refers o placing increased demands on the body? A. Specificity B. cross-training c.type D.overload
Anuta_ua [19.1K]
Overload <<<<<<<<<<<<<<<<<<<<<<<<<<<<<,,,,,,,,
5 0
3 years ago
The speed of a car is decreased uniformly from 30. meters per second to 10. meters per second in 4.0 seconds. What was the car's
masha68 [24]
Acceleration (magnitude anyway) = (change in speed) / (time for the change) .

Change in speed = (10 - 30) = -20 m/s

Time for the change = 4.0sec

Magnitude of acceleration = -20/4  =  <em>-5 m/s² </em>
3 0
3 years ago
Read 2 more answers
A 1.2 kg ball drops vertically onto a floor from a height of 32 m, and rebounds with an initial speed of 10 m/s.
iren [92.7K]

Explanation:

Given that,

Mass of the ball, m = 1.2 kg

Initial speed of the ball, u = 10 m/s

Height of the floor from ground, h = 32 m

(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 32}

v = -25.04 m/s (negative as it rebounds)

The impulse acting on the ball is equal to the change in momentum. It can be calculated as :

J=m(v-u)

J=1.2\times (-25.04-10)

J = -42.048 kg-m/s

(b) Time of contact, t = 0.02 s

Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :

J=\dfrac{F}{t}

F=J\times t

F=42.048\times 0.02

F = 0.8409 N

Hence, this is the required solution.

5 0
3 years ago
How many watts are used when 6000 joules of energy are consumed in 5 hours?
Ray Of Light [21]
Power = energy / time
Time should be in seconds
5 hours = 5 × 60 minutes = 5 × 60 ×60 seconds = 18000 s
Power = 6000/18000 = 0.333 W

Hope it helped!
7 0
3 years ago
Hat do peaked roofs, convertible tops, and airplane wings have in common when air moves faster across their top surfaces? What d
Nutka1998 [239]

Answer:

a.

Explanation:

The air moves faster across the top of the surface and exerts less pressure on the air below and thus due to difference in air pressure the top roof is lifted.

hence the correct option is pressure underneath them is reduced.

6 0
3 years ago
Read 2 more answers
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