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Monica [59]
3 years ago
7

What condition is necessary for an object to make a good reference point?

Physics
1 answer:
777dan777 [17]3 years ago
8 0
The object is fixed relative to the motion you are trying to describe.
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A man stands still on a moving walkway that is going at a speed of 0.2 m/s to
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Answer:

0.2 m/s east

Explanation:

mark as brainlyest

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3 years ago
A point charge of 5.0 x 10^-7 C moves to the right at 2.6 x 10^5 m/s in a magnetic field that is directed into the screen and ha
-BARSIC- [3]

The magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

<h3>What is magnetic force?</h3>

A magnetic force is the force that act in a magnetic field.

To calculate the magnetic force, we use the formula below.

Formula:

  • F = qvB.........Equation 1

Where:

  • F = magnetic force
  • q = point charge
  • v = Velocity of the the charge
  • B = Field strength

From the question,

Given:

  • q = 5.0×10⁻⁷ C
  • v = 2.6×10⁵ m/s
  • B = 1.8×10⁻² T

Substitute these values into equation 2

  • F = (5.0×10⁻⁷)(2.6×10⁵)(1.8×10⁻²)
  • F = 23.4×10⁻⁴
  • F = 2.34×10⁻³ N

Hence, the magnitude of the magnetic force acting on the charge is 2.34×10⁻³ N.

Learn more about magnetic force here: brainly.com/question/2279150

#SPJ12

5 0
2 years ago
The timeline below shows some major discoveries in biology.
34kurt

Answer:

The cell theory

Explanation:

3 0
3 years ago
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If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar
AnnyKZ [126]

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}

when the frequency is doubled

\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1

Thus, the angular frequency will be doubled.

Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}

when the frequency is doubled;

T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}

Thus, the period will be reduced to one-half of what it was.

5 0
3 years ago
If you ride a bike at an average speed of 6 km/h and need to travel a total
Fiesta28 [93]

Answer:

5 hours

Explanation:

formula is 6 km per hour

if you have to travel 30 km, divide 30 by 6

30/6 = 5 hours

5 0
2 years ago
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