Answer: 586.60N/m
Explanation:
In this scenario, the elastic potential energy of the spring is converted into potential energy.
0.5*K*x^2 = mgh
Thus K = 2mgh/x^2
=(2*2.90*10^-2*9.8*7.23)/(8.37*10^-2)^2
=586.599
Therefore K = 586.60N/m
Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
E = ½(0.1 kg)(2 m/s)² + (0.1 kg)(9.8 m/s²)(1.5 m)
E = 0.2 J + 1.47 J
E = 1.67 J
False i just took the test and put true as a guess but got it wrong so it is false
please give me a brainlies
We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is
Where,
F_D = Drag Force
= Drag coefficient
A = Area
= Density
V = Velocity
Our values are given by,
(That is proper of a cone-shape)
Part A ) Replacing our values,
Part B ) To find the torque we apply the equation as follow,
Speed uses distance and velocity uses displacement in its calculation.
For 100 m race, distance = displacement. Hence speed = velocity
For 400m race, distance ≠ displacement. distance = 400m whereas displacement = 0m. Hence speed ≠ velocity
