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erik [133]
3 years ago
5

The answer please to this and how it’s urgent

Physics
1 answer:
oksano4ka [1.4K]3 years ago
6 0

Answer:

rA = 9 i + 9 j

rB = 12 i - 9 j

rB - rA = 3 i - 18 j

so distance in between them

= √[3×3 + 18 × 18 )

= √(9+324)

= √333

= 18.3 m

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Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer
Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

I' = I_{0}Cos^{2}\theta     .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

I'' = I'Cos^{2}\left ( 90-\theta \right )

So,

I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )

I'' = I_{0}Cos^{2}\theta Sin^{2}\theta

I'' = \frac{I_{0}}{4}Sin^{2}2\theta

(b)

Now differentiate with respect to θ.

I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta

I'' = \frac{I_{0}}{2}\times Sin 4\theta

7 0
3 years ago
A projectile enters a resisting medium at x = 0 with an initial velocity v0 = 910 ft/s and travels 5 in. before coming to rest.
evablogger [386]

Answer:

a = - 1.987 × 10⁶ ft/s²

t = 6.84 × 10⁻⁴ s

Explanation:

v₀ = 910 ft/s

x = 5 in.

relation v = v₀ - k x

v = 0 as body comes to rest

0 = 900 - 5k/12

k = 2184 s⁻¹

acceleration

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

where

(A) a = -k × v

 at v= 910 ft/s

     a = - 1.987 × 10⁶ ft/s²

(B)  at x = 3.9 in.

v = 910 - 3.9(2184)/12

v = 200.2 m/s

\frac{\mathrm{d} v}{\mathrm{d} t} = -k\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{dv}{v} = -kdt

\int\limits^{200.2}_{900} {\frac{1}{v} }dv = -k\int\limits^t_0 dt

ln(200.2)-ln(900) = -kt

t = 6.84 × 10⁻⁴ s

3 0
3 years ago
Match the layers of the atmosphere with the description that best matches it according to the graph titled Temperature Profile.
Finger [1]
The correct matches are as follows:

<span>Troposphere
A) Layer closest to the Earth where all weather occurs

Mesosphere
</span>C) temperature remains constant as elevation increases<span>

Mesopause
</span>D) temperature remains at a constant zero degrees Celsius as elevation increases<span>


Stratosphere
</span>E) begins between 50-60km and decreases in temperature as elevation increases <span>


Stratopause
</span> B) temperature increases as elevation increases


Hope this answers the question. Have a nice day.
3 0
3 years ago
Read 2 more answers
Some earthquake waves, a cat’s purr, and elephant communications consist of ultrasonic waves.
Kobotan [32]
The answer to your question is true.
7 0
3 years ago
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What is the weight of a 500g ball? (gravity is 9.8 m/s)​
vovangra [49]

Answer:

4,900

Explanation:

you find the weight by multiplying the ball in grams to the gravity

7 0
3 years ago
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