Answer:
The moles of starting material is
mole
Explanation:
Given:
Cyclohexene oxide material is used
Density = 0.97
Volume = 1.84 mL
Formula of Cyclohexene oxide = 
Molar mass is given by,



⇒ 
Mass

Moles is given by,


mol
Therefore, the moles of starting material is
mole
Answer:
C8H12F6
Explanation:
To solve this question we need to find the moles of each atom in order to find the empirical formula (The empirical formula is defined as the simplest whole-number ratio of atoms present in a molecule). Using the empirical formula and the molar mass we can find molecular formula as follows:
<em>Moles C:</em>
2.35g * (1mol / 12g) = 0.1958 moles C
<em>Moles H:</em>
0.294g (1mol /1g) = 0.294 moles H
<em>Moles F -Molar mass: 19.0g/mol-: </em>
Mass F: 5.43g - 2.35g C - 0.294g H = 2.786g F * (1mol / 19.0g) = 0.1466 moles F
The moles of atoms dividing in the moles of F (Lower number of moles) produce the simplest ratio as follows:
C = 0.1958mol C / 0.1466mol F = 1.33
H =0.294mol H / 0.1466mol F = 2
F = 0.1466 mol F / 0.1466mol F = 1
As the empirical formula requires whole numbers, this ratio multiplied 3 times:
C = 4
H = 6
F=3
The empirical formula is:
C4H6F3
With molar mass of:
4C = 12*4 = 48
6H = 1*6 = 6
3F = 19*3 = 57
The molar mass is: 48g/mol + 6g/mol + 57g/mol = 111g/mol
As we know the molecule has a molar mass between 219-225g/mol and the empirical formula is 111g/mol, 2 times empirical formula will produce a molecule with the molar mass of the molecule, that is:
<h3>C8H12F6</h3>
Answer:
yes
Explanation:
because this is a neutralization reaction that yield salt and water
Water's relatively small size allows it to fit between individual atoms, driving them apart. Water's hydrophobic nature separates polar and non-polar substances. Water's polarity allows it to dissolve ionic and polar compounds.
Answer:
1.37 x
CFU/mL
Explanation:
First, the dilution factor needs to be calculated.
Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of
.
Next is to divide the colony forming unit from the dilution by the dilution factor:
137/
= 137 x 
In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.
137 x
/1 = 1.37 x 
Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x
.
cfu/ml = (no. of colonies x dilution factor) / volume of culture plate