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3 years ago

Before finishing and installing a shelved cabinet you just constructed, you need to check the

Engineering

1 answer:

Greeley [361]3 years ago

7 0

Answer:

Carpenter's square

Explanation:

The most common hand tool used to measure or set angles with its application extending to setting angles of roofs and rafters. Another name of a Carpenter's square is a framing square.

Other hand tools that are used to measure angles are;

The combination square that allows a user to set both 90° and 45° angles
A Bevel that allows users to set any angle they like.
A Protractor that resembles a bevel but its marks are marked in an arc.
An electromagnetic angle finder which gives a reading according to the measure of the arms adjusted by the user.

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A binary liquid system exhibits LLE at 25°C. Determine from each of the following sets of miscibility data estimates for paramet

Phoenix [80]

Answer:

(a) - A12 = A21 = 2.747

(b) - A12 = 2.148; A21 = 2.781

(c)- A12 = 2.781; A21 = 2.148

Explanation:

(a) - x1(a) = 0.1 | x2(a) = 0.9 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

x1(a)*γ1(a) = x1(b)γ1(b)

x2(a)*γ2(a) = x2(b)γ2(b)

A12 = A21 = 2.747

(b) - x1(a) = 0.2 | x2(a) = 0.8 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

x1(a)*γ1(a) = x1(b)γ1(b)

x2(a)*γ2(a) = x2(b)γ2(b)

A12 = 2.148; A21 = 2.781

(c) - x1(a) = 0.1 | x2(a) = 0.9 | x1(b) = 0.8 | x2(b) = 0.2

LLE equations:

x1(a)*γ1(a) = x1(b)γ1(b)

x2(a)*γ2(a) = x2(b)γ2(b)

A12 = 2.781; A21 = 2.148

7 0

3 years ago

Consider two Carnot heat engines operating in series. The first engine receives heat from the reservoir at 1400 K and rejects th

Aleksandr-060686 [28]

Answer:

The temperature T= 648.07k

Explanation:

T1=input temperature of the first heat engine =1400k

T=output temperature of the first heat engine and input temperature of the second heat engine= unknown

T3=output temperature of the second heat engine=300k

but carnot efficiency of heat engine = $1 - \frac{Tl}{Th} \\$

where Th =temperature at which the heat enters the engine

Tl is the temperature of the environment

since both engines have the same thermal capacities <em> $n_{th}$ </em> therefore $n_{th} =n_{th1} =n_{th2}\\n_{th }=1-\frac{T1}{T}=1-\frac{T}{T3}\\ \\= 1-\frac{1400}{T}=1-\frac{T}{300}\\$

We have now that

$\frac{-1400}{T}+\frac{T}{300}=0\\$

multiplying through by T

$-1400 + \frac{T^{2} }{300}=0\\$

multiplying through by 300

- $420000+ T^{2} =0\\T^2 =420000\\\sqrt{T2}=\sqrt{420000} \\T=648.07k$

The temperature T= 648.07k

5 0

3 years ago

Document the XSS stored exploit script: Use the View Source feature of the web page and create a screenshot of the few lines cod

Natali [406]

Answer:

Hold on let me ask my brother

Explanation:

5 0

3 years ago

Voltage drop testing is being discussed.

Airida [17]

Answer:

Technician B only is correct

Explanation:

Voltage drop testing is a method used to find the amount of electrical resistance available in an high amperage circuit that involves connecting the leads of the meter in parallel to the circuits being tested such that disassembly is not required

In voltage drop test, the red voltmeter lead and black voltmeter lead are placed at two points on the same side of the circuit connection such that the leads are in between two positive connection or two negative connection (rather than connecting the red to the positive and the black to the negative sides of the circuit) and digital voltmeter is used for the voltage drop measurement across the lead while the connection is under load.

Therefore, Technician B only is correct

8 0

2 years ago

The in-situ dry density of a sand is 1.72Mg/m3. The maximum and minimum drydensities, determined by standard laboratory tests, a

Stells [14]

Answer:

Relative density = 0.7 or 70%

Explanation:

The following information was provided by this question

Pd = 1.72mg/mg³

Pd max = 1.81 mg/mg³

Pd min = 1.54 mg/mg³

We substitute into the formula. This formula is contained in the attachment.

[(1/1.54)-(1/1.72)]/[1/1.54 - 1/1.81]

= 0.649350 - 0.581395 / 0.649350 - 0.552486

= 0.067955/0.096864

= 0.7015

= 0.7

The relative density is Therefore 0.7 or 70% when converted to percentage

8 0

2 years ago