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MakcuM [25]
3 years ago
14

In which item is energy stored in the form of gravitational potential energy? A. A slice of bread B. A compressed spring C. An a

pple on a tree D. A stretched bow string
Physics
2 answers:
Blababa [14]3 years ago
8 0

Answer:

C) an apple on a tree

Explanation:

marysya [2.9K]3 years ago
3 0

The things that determine the amount of an object's gravitational potential energy are ...

-- mass of the object

-- gravitational acceleration in the place where the object is

-- height of the object above the ground or the floor

A). <em>a slice of bread; </em> No.  It's still a slice of bread even if it's on the ground.

B. <em>A compressed spring; </em> No.  It's still a compressed spring even if it's on the ground.

C. <em>An apple on a tree</em>; <em>Yes !</em>  It can't be an apple on a tree if it's on the ground.  

D. <em>A stretched bow string</em>; <em>No.</em>  It's still a stretched bowstring even if it's on the ground.

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How many band is the parametric microphone equalizer?
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Answer:

3 bands

Explanation:

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8 0
2 years ago
Consider two point charges located on the x axis: one charge, q1 = -11.5nC , is located at x1 = -1.685m ;the second charge, q2 =
Nata [24]

Answer:

F_{t3}=-3.76\ 10^{-5}\ N

The net force is pointed to the left side

Explanation:

Electrostatic Force

The formula to compute the electrostatic force between two point charges was introduced by Charles Coulomb and it's expressed as

\displaystyle F=\frac{k\ q_1\ q_2}{r^2}

Where q1 and q2 are the magnitudes of the charges, r is the distance between them and k is a proportionality constant

The data provided in the problem is

\displaystyle x_1=-1,685\ m

\displaystyle q_1=-11.5\ nC

\displaystyle q_2=40\ nC

\displaystyle q_3=55\ nC

\displaystyle x_3=-1.195\ m

The distance between the charge 1 and 3 is

\displaystyle d_{13}=1.685-1.195

\displaystyle d_{13}=0.49\ m

The distance between charges 2 and 3 is

\displaystyle d_{23}=1.195\ m

Now, let's compute the force exerted by q1 on q3

\displaystyle F_{13}=\frac{k\ q_1\ q_3}{d_{13}^2}

\displaystyle F_{13}=\frac{9\ 10^9\ 11.5\ 10^{-9}\ 55\ 10^{-9}}{0.49^2}

\displaystyle F_{13}=2.37\ 10^{-5}\ N

This value is the scalar magnitude of the force, we'll take care of the directions later. The force by q2 on q3 is

\displaystyle F_{23}=\frac{k\ q_2\ q_3}{d_{23}^2}

\displaystyle F_{23}=\frac{9\ 10^{9}\ 40\ 10^{-9}\ 55\ 10^{-9}}{1.195^2}

\displaystyle F_{23}=1.39\ 10^{-5}\ N

Given that q1 is negative and q3 is positive, q1 attracts q3 to the left, so F13 is in the negative direction. The charge q2 is positive and repels q3 to the left, thus F23 is also negative. This leads us to compute the total force on q3 as

\displaystyle F_{t3}=-F_{13}-F_{23}

\boxed{F_{t3}=-3.76\ 10^{-5}\ N}

The net force is pointed to the left side

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