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3 years ago

What affects the braking distance and thinking distance

2 answers:

8 0

Your speed is one of the only factors that has an effect on both your thinking distance and braking distance. Put simply, the faster you are going, the greater the distance travelled before you apply the brakes (thinking distance) and the vehicle comes to a complete stop (braking distance).

hodyreva [135]3 years ago

8 0

Several many things do.

Thinking distance: speed, driver's alertness or fatigue, light or dark outside, distractions inside the car, distractions outside the car, driver on the phone

Braking distance: speed, size and weight of the car or truck, condition of the tires, the road surface: wet or dry, concrete or tar, dirt or gravel

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The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul

ozzi

The correct answer is
B It increases.

In fact, the kinetic energy of a moving object is given by
$K= \frac{1}{2}mv^2$
where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.

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3 years ago

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In order for an object to have a perfectly circular orbit, what one thing must occur?

ryzh [129]

Answer:

The second one is correct.

Explanation:

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3 years ago

A current of 310 amps is flowing through a copper wire with a resistance of 30 ohms. What is the voltage?

torisob [31]

Answer:

the voltage is 930V

Explanation:

U=I*R

U=310*30=930V

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3 years ago

Can anyone fill in the blanks for the potential and kentic energy? Also, is this showing energy transformation? Thank you so muc

Bezzdna [24]

Potential Kinetic Kinetic Potential Potential

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3 years ago

A car traveling at 43 km/h hits a bridge abutment. A passenger in the car moves forward a distance of 54 cm (with respect to the

Brums [2.3K]

Answer:

F = -6472.9 N

F= -6.47 kN

Explanation:

First of all you have to convert the data to SI units

so for the velocity you have :

Vi = 43km/h *(1000m/1km)*(1h/3600s) ---> using conversion factors

Vi= 11.9444 m/s

dX : distance the passanger moves

dX = 54cm*(1m/100cm) --> using conversion factors

dX = 0.54 m

Now to calculate the force we are going to use the sum of focers equals to mass for acceleration:

Sum F = m*a

We have to find a so we are going to use the velocity's formula as follows to solve a:

Vf ^2 = Vi^2 +2*a*dX

Vf=0 --> the passenger does not move after the airbag inflates.

a= -(Vi^2)/(2*dX)

you solve de acceleration with the data you hae and you will find

a = -132.1 m/ s^2

Now you can solve the Sum F equation

Sum F = 49 Kg * (-132.1 m/s^2)

F = -6472.9 N

F= -6.47 kN

6 0

3 years ago