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UNO [17]
3 years ago
9

What number represents neutral?

Chemistry
1 answer:
Semmy [17]3 years ago
4 0
7. Neutralisation. Which would (obviously) appear GREEN on the chart.
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What mass of sucrose, C12H22011, is needed to make 500.0 mL of a 0.200M<br> solution?
NeX [460]

Answer:

34.23 g

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0
3 years ago
Lithium, sodium and potassium all belong to the same group of the periodic table.
Lady_Fox [76]

Answer:

Yes they are found in same period

4 0
3 years ago
Read 2 more answers
A pure gold ring weighs 23.5 grams. How many atoms of gold<br> are in the ring?
Digiron [165]

The number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

<h3>HOW TO CALCULATE NUMBER OF ATOMS?</h3>

The number of atoms in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

The number of moles in the gold (Au) can be calculated by dividing the mass of gold by its molar mass (196.97g/mol).

no. of moles = 23.5g ÷ 196.97g/mol

no. of moles = 0.119mol

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no. of atoms = 7.18 × 10²² atoms.

Therefore, the number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

Learn more about number of atoms at: brainly.com/question/15959704

3 0
3 years ago
How can you prove copper is a catalyst?
jolli1 [7]
There is no way to know which reaction requires which catalyst. However, if you apply copper to a reaction where it does act as a catalyst, the rate of reaction will be much faster as it lowers the activation energy for successful collisions. 
3 0
3 years ago
i have an unknown volume of gas at a pressure of 0.50 atm a temperature of 325 k. If i raise the pressure to 1.2 atm, decrease t
Ronch [10]
Assuming that the number of mols are constant for both conditions:
\frac{P_1V_1}{T_1} =  \frac{P_2V_2}{T_2}
Now you plug in the given values. V_1 is the unknown. 
\frac{0.50 atm*V_1}{325K} = \frac{1.2 atm* 48 L}{230K}&#10;
Separate V_1
V_1= \frac{1.2 atm* 48 L * 325K }{230K*0.50 atm }
V= 162.782608696 L 

There are 2 sig figs

V= 160 L
3 0
3 years ago
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