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3 years ago

What can a drop of liquid mercury be described as

Physics

2 answers:

jeka943 years ago

7 0

It can be described as <span>a pure substance and an element. </span>

Mrac [35]3 years ago

4 0

The answer is a pure substance and an element.

Hope this helps!!! :)

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Induced EMF and Current in a Shrinking LoopShrinking Loop. A circular loop of flexible iron wire has an initial circumference of

vodomira [7]

Answer:

Explanation:

Let c be the circumference and r be the radius

c = 2πr , r = c / 2π , area A = π r² = π (c/2π )² = (1/4π) x c²

flux (ψ) = BA = 1 X 1/4π X c²

dψ/dt = 1/4π x 2c dc/dt =1/2π x c x dc/dt

at t = 8 s

c = 161 - 13 x 8 = 57 cm , dc/dt = 13 cm/s

e = dψ/dt = (1 / 2π )x 57 x 13 x 10⁻⁴ = 118 x 10⁻⁴ V.

4 0

3 years ago

Your house is 45.0 m from a powerline carrying 152 A of current. How much magnetic field does the current create at your house?

Sedaia [141]

This question involves the concepts of th magnetic field and current.

The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".

<h3>Magnetic Field</h3>

The magnetic field created by a current carrying wire can be given by the following formula:

$B=\frac{\mu_o I}{2\pi r}$

where,

B = magnetic field = ?
$\mu_o$ = permeabiliy of free space =4π x 10⁻⁷
I = current = 152 A
r = distance = 45 m

$B=\frac{4\pi x\ 10^{-7}(152)}{2\pi(45)}$

B = 6.75 x 10⁻⁷ T

Learn more about magnetic field here:

brainly.com/question/23096032

#SPJ1

7 0

1 year ago

A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in

koban [17]

Answer:

a) The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) The electric force is $2.0\times 10^{-6}$ newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

$E = \frac{F_{e}}{q}$ (1)

Where:

$E$ - Electric field, measured in newtons per coulomb.

$F_{e}$ - Electric force, measured in newtons.

$q$ - Electric charge, measured in coulombs.

If we know that $F_{e} = 4.0\times 10^{-6}\,N$ and $q = 2.0\times 10^{-8}\,C$ , then the electric field at that point is:

$E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}$

$E = 2.0\times 10^{2}\,\frac{N}{C}$

The electric field at that point is $2.0\times 10^{2}$ newtons per coulomb.

b) If we know that $E = 2.0\times 10^{2}\,\frac{N}{C}$ and $q = 1.0\times 10^{-8}\,C$ , then the electric force is:

$F_{e} = E\cdot q$

$F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)$

$F_{e} = 2.0\times 10^{-6}\,N$

The electric force is $2.0\times 10^{-6}$ newtons.

7 0

3 years ago

All objects _<br> energy.

Alekssandra [29.7K]

Answer:

Explanation:

All objects <u>radiate</u> energy.

8 0

2 years ago

Two cars are moving in the same direction at the same speed of (72.0 kmh). What is

Licemer1 [7]

Answer:

0 km/h

Explanation:

Relative speed is the speed of a moving body with respect to another.

When two bodies move in the same direction then the relative speed is calculated as difference of their speeds.

In this case;

The two cars have the same speed. The relative speed will be;

72 km/h -72 km/h = 0 km/h

6 0

2 years ago