Mass of 25 kg weight is 25/9.81 slug of mass.
Missing graph. I attach it in the answer.
In a uniformly accelerated motion, the velocity at time t is given by:

where a is the acceleration and t is the time.
Given the previous equation, if we plot v(t) versus t, we find a straight line; moreover, a (the acceleration) represents the slope of the curve.
Looking at the graph, we see that when the time goes from 10 s to 20 s, the velocity increases from 4 m/s to 6 m/s. Therefore the slope of the curve is

and this corresponds to the acceleration.
So, the correct answer is <span>
0.2 m/s2.</span>
Answer:
C and D
Explanation:
A uniform probability model is a probabilistic model characterized by a uniform probability density function, or uniform distribution.
In common language, a uniform probability distribution means that all possible outcomes in the probability space have the same probability of occurrence.
So:
- A fair toss of coin every possible outcome (H,T) has probability 0.5. It is modeled by by a uniform discrete distribution.
- Randomly selected answer to an MCQ with four options would have probability of success 0.25 for every MCQ. It is modeled by by a uniform discrete distribution.
- Spinning a spinner with sections that are different sizes, each section would have different probabilities proportional to the coverage area on the. It is modeled by a non-uniform discrete distribution
- Pulling a red marble out of a bag with 6 red marbles, 3 green marbles, and 1 yellow marble. Each successive time a red marble is drawn the probability decreases. Hence, non uniform distribution.
- Spinning a spinner on which all sections are the same size. Each section would have similar probabilities proportional to the coverage area on the. It is modeled by a uniform discrete distribution .
Answer: 29.50 m
Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:
f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).
f=m.a=μ*N= m*a= μ*m*g= m*a
then
a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2
With this value we can determine the short distance to stop the train
as follows:
x= vo*t- (a/2)* t^2
Vf=0= vo-a*t then t=vo/a
Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m