An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time
1 answer:
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Answer:
Explanation:
P = Acoustic power = 63 µW
r = Distance to the sound source = 210 m
Acoustic power
Threshold intensity =
Ratio
Ratio of the acoustic intensity produced by the juvenile howler to the reference intensity is 113.68
Answer:
Explanation:
m = Masa del coche
g = Aceleración debida a la gravedad =
h = Altura =
v = Velocidad del automóvil en la parte inferior de la pista
Aquí asumimos que el automóvil desciende verticalmente. La energía potencial del automóvil se completará convertida en energía cinética en la parte inferior de la pista ya que no hay pérdida de energía.
La velocidad máxima que puede alcanzar el coche es .
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
And so
And using
, we find K2:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
And so
And using