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coldgirl [10]
3 years ago
13

He original height of the leaning tower of pisa was 184 feet. at a distance of 140 feet from the base of the tower, the angle of

elevation from the ground to the top of the tower is . how far is the tower leaning from the original vertical position?

Physics
2 answers:
ratelena [41]3 years ago
8 0

Answer:

37.3°

Explanation:

The angle of elevation can be found by using trigonometric tan function.

tan \theta = \frac {perpendicular}{base}

perpendicular is given by the height of the tower = 184 ft

base = distance from the tower = 140 ft

Thus, angle of elevation:

\theta = tan^{-1}(\frac{184}{140})=tan^{-1}{1.31}\\ \Rightarrow \theta = 52.7^o

Now, the angle of elevation + angle made by tower from the original vertical position towards the ground = 180 -90

⇒Ф= 90° - 52.7° = 37.3°

vladimir2022 [97]3 years ago
7 0

Ans:; 

Let AB be the height of the leaning tower= 184 feet

Let AC be the distance from the base of the tower= 140 feet

Angle between BC and AC = 59 degrees

Applying the sine rule

AB/(Sin 59) = 140/(Sin B)

On cross multiplication we get, check image, 


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Hello!

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Solving:

It is noteworthy that chemical elements located on the periodic table in the lanthanide and actinide groups are radioactive.  

Am-241 (americium) belongs to the group of actinides and is a heavy and radioactive metal.  

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Pu-241 (plutonium) is an element that is isotope of fission by plutonium, belongs to the group of actinides and is a heavy and radioactive metal.  

U-238 (uranium) is an element that is isotope of non-fission uranium, belongs to the group of actinides and is a heavy and radioactive metal.

Answer:

B) Mg-24

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I Hope this helps, greetings ... Dexteright02! =)

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