Answer:
Explanation:
The question is incomplete.
The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.
s= sin2(pi)t
Acceleration = d²S/dt²
dS/dt = 2πcos2πt
d²S/dt² = -4π²sin2πt
A(t) = -4π²sin2πt
Next is to find acceleration after 4.5 seconds
A(4.5) = -4π²sin2π(4.5)
A(4.5) = -4π²sin9π
A(4.5) = -4π²sin1620
A(4.5) = -4π²(0)
A(4.5) = 0m/s²
The main difference between baseline activities and health-enhancing activities is that baseline activities maintain the status quo, while health-enhancing activities make things better.
Mass is a base unit, acceleration is a derived unit calculated as a function of length and time which are both base units. Any unit definition that is a function of more basic units is considered a derived unit. ~Quora.com
Answer:
532.0725 m
102.17270893 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s² = g
H = Height of cliff
Distance traveled in 3 seconds
![s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 3^2\\\Rightarrow s=44.145\ m](https://tex.z-dn.net/?f=s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D0%5Ctimes%20t%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.81%5Ctimes%203%5E2%5C%5C%5CRightarrow%20s%3D44.145%5C%20m)
Distance traveled by sound = 2H-44.145 m
![2H-44.145=ut+\dfrac{1}{2}at^2\\\Rightarrow 2H-44.145=340\times 3\\\Rightarrow H=\dfrac{340\times 3+44.145}{2}\\\Rightarrow H=532.0725\ m](https://tex.z-dn.net/?f=2H-44.145%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%202H-44.145%3D340%5Ctimes%203%5C%5C%5CRightarrow%20H%3D%5Cdfrac%7B340%5Ctimes%203%2B44.145%7D%7B2%7D%5C%5C%5CRightarrow%20H%3D532.0725%5C%20m)
The height of the cliff is 532.0725 m
![v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 532.0725+0^2}\\\Rightarrow v=102.17270893\ m/s](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2as%2Bu%5E2%7D%5C%5C%5CRightarrow%20v%3D%5Csqrt%7B2%5Ctimes%209.81%5Ctimes%20532.0725%2B0%5E2%7D%5C%5C%5CRightarrow%20v%3D102.17270893%5C%20m%2Fs)
Her speed just before she hits the ground is 102.17270893 m/s
light waves do not require a medium so A would be your answer good luck :)