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Kazeer [188]
3 years ago
12

Using Charles law if the volume of a gas is 5.0 L when the temperature is 5.0C what will the new volume be if the temperature is

raised to 10C and the pressure remains the same
Chemistry
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

The answer to your question is   V2 = 5.09 l

Explanation:

Data

Volume 1 = V1 = 5.0 L

Temperature 1 = T1 = 5°C

Volume 2 = V2 = ?

Temperature 2 = T2 = 10°C

Formula (Charles law)

             V1/T1 = V2/T2

-Solve for V2

                  V2 = V1T2 / T1

-Convert temperature to °K

T1 = 5 + 273 = 278°K

T2 = 10 + 273 = 283°K

-Substitution

                 V2 = (5)(283) / (278)

-Simplification

                 V2 = 1415 / 278

-Result

                 V2 = 5.09 l

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Answer:

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Explanation:

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A neutralization reaction is a chemical reaction where an acid and a base are combined with the intent of producing a neutral pH level.

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2 years ago
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8 0
3 years ago
What will be the volume of a gas sample at 358 K if its volume at 255 K is 7.4 L?
Jobisdone [24]

Answer:

10.4 L

Explanation:

V1/T1=V2/T2

V2= (V1*T2)/T1

V2= (7.4L * 358K)/255K

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3 years ago
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2 years ago
How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?
maks197457 [2]

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

8 0
3 years ago
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