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3 years ago

8

Which layer of the atmosphere is just above the troposphere?

1 answer:

boyakko [2]3 years ago

6 0

The answer would Stratosphere because <span>1) The </span>troposphere<span> is the first </span>layer above<span> the surface and contains half of the Earth's </span>atmosphere<span>. Weather occurs in this </span>layer. 2) Many jet aircrafts fly in thestratosphere<span> because it is very stable. Also, the ozone </span>layer<span> absorbs harmful rays from the Sun</span>

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A 1.2 kg hammer slams down on a nail at 5.0 m/s and bounces off at 1.0 m/s. If the impact lasts 1.0 ms, what average force is ex

Delvig [45]

Answer:

Explanation:

Impulse results in a change of momentum

FΔt = mΔV

F = mΔV/Δt

The impulse acting on the hammer will equal the impulse acting on the nail

If we assume upward is the positive direction

F = m(vf - vi)/t

F = 1.2(1.0 - (-1.5)) / 0.001

F = 3000 N

7 0

2 years ago

When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

Lilit [14]

Answer:60 gm

Explanation:

Given

initial velocity of ball $u=0$

Force exerted by racquet $F=540 N$

time period of force $t=5\ ms$

final velocity of ball $v=45\ m/s$

Racquet imparts an impulse to the ball which is given by

$J=F\Delta t=\Delta P$

$J=540\times \Delta t=m(45-0)$

$m=\frac{540\times 5\times 10^{-3}}{45}$

$m=60\ gm$

8 0

3 years ago

The highest energy waves have the<br> {SHORTEST}wavelength

Likurg_2 [28]

Answer:

infared rays pls give me brainiest]

8 0

2 years ago

Which scientist did this?

Colt1911 [192]

You answer would be C. Ernest Rutherford.

4 0

3 years ago

Read 2 more answers

A roller coaster at the Six Flags Great America amusement park in Gurnee, Illinois, incorporates some clever design technology a

Zigmanuir [339]

Answer:

5.95 m

Explanation:

Given that the biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g

For the car to stick to the loop without falling down, at the top of the ride, the centripetal force must be equal to the weight of the car. That is,

(MV^2) / r = mg

V^2/ r = centripetal acceleration which is equal to 2g

2 × 9.8 = 10.8^2 / r

r = 116.64 /19.6

r = 5.95 m

3 0

3 years ago