Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
or,
..........(1)
where,
= rate of effusion of nitrogen gas = 
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:
Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.
Answer:
has two double C-C bonds
Explanation:
A saturated compound is a compound having the full complement of hydrogen atoms for every carbon atom while an unsaturated compound does not contain the full complement of hydrogen atoms for every atom of carbon.
If we look at C3H4, the only possible structure of the compound is H2C=C=CH2. We can see from this arrangement that the compound contains a cumulative double bond. This is the specific structure that fits into one of the descriptions in the options, the compound contains two double bonds.
Fe2O3 + 2Al => Al2O3 + 2Fe↓
reaction of changing.
In this type of reaction one element or group of elements from one substance is changed with a single element.
Answer:
D
Explanation:
Measurements that are close to a standard measured value is accurate. But when measured values are close to each other they are precise. For example, if one measures the weight of 1 kg of rice as 945 g and another person measure it as 955 g, then the second person’s ,measurement is more accurate. Now if the first person measured the same bag of rice thrice and got values 945 g, 946 g and 947g whereas the second person got values 955g, 950 g and 940 g, in such a case the first person’s measured value is more precise.
Molarity is a unit of concentration defined as the number of moles of solute (the substance being dissolved) per volume of solution (the solvent in which all the solute is dissolved). Mathematically, molarity is expressed as
.
In this question, we are given the molarity and the volume of a solution of NaCl. We can use this information to calculate the number of moles of NaCl present in the solution. Rearranging the equation to solve for moles of solute, we multiply the molarity by the volume of the solution (the units for volume must be in liters, so 125 mL is expressed as the equivalent 0.125 L):
The question asks for the number of moles of NaCl in this solution, so number 3 would be correct.
