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4 years ago

From which end (north or south) of a bar magnet do magnetic field lines emerge?

1 answer:

5 0

They emerge from the north end. In modern magnetics we don't use the idea of north and south anymore but instead use a vector called the magnetization. It points toward what is traditionally called "north".

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3 years ago

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Magnetic Energy density affected by area?

Mademuasel [1]

Answer:

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3 years ago

Jake drops a book out of a window from a height of 10 meters. At what velocity does the book hit the ground?

user100 [1]

G = 9.81 m/sec^2) g = 9.81 $\frac{meters}{ second^{2} }$

Solving for velocity : 

$velocity^{2}$ = 2gh 
v = $2gh^{ \frac{1}{2} }$
v = (2 x 9.81 x 10)^1/2 
v = 196.2 m/sec (answer)

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3 years ago

(a) How many fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit

Ainat [17]

Answer:

The number of fringe is z = 3 fringes

The ratio is $I = 0.2545I_o$

Explanation:

From the question we are told that

The wavelength is $\lambda = 600 nm$

The distance between the slit is $d = 0.117mm = 0.117 *10^{-3} m$

The width of the slit is $a = 35.7 \mu m = 35.7 *10^{-6}m$

let z be the number of fringes that appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern is and this mathematically represented as

$z = \frac{d}{a}$

Substituting values

$z = \frac{0.117*10^{-3}}{35.7 *10^{-6}}$

z = 3 fringes

From the question we are told that the order of the bright fringe is n = 3

Generally the intensity of a pattern is mathematically represented as

$I = I_o cos^2 [\frac{\pi d sin \theta}{\lambda} ][\frac{sin (\pi a sin \frac{\theta}{\lambda } )}{\pi a sin \frac{\theta}{\lambda} } ]$

Where $I_o$ is the intensity of the central fringe

And Generally $sin \theta = \frac{n \lambda }{d}$

$I = I_o co^2 [ \frac{\pi (\frac{n \lambda}{d} )}{\lambda} ] [\frac{\frac{sin (\pi a (\frac{n \lambda}{d} ))}{\lambda} }{\frac{\pi a (\frac{n \lambda}{d} )}{\lambda} } ]$