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3 years ago

How do fossils provide evidence of continental drift?

1 answer:

8 0

C explanation: There are many examples of fossils found on separate continents and nowhere else, suggesting the continents were once joined. If Continental Drift had not occurred, the alternative explanations would be: They swam to the other continent/s in breeding pairs to establish a second population. ...

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1. Is the relationship between velocity and centripetal force a direct, linear relationship or is it a nonlinear square relation

Svetllana [295]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

7 0

3 years ago

The magnetic field of a light wave oscillates parallel to a y axis and is given by by = bmsin(kz – ?t. (a in what direction does

-Dominant- [34]

In this case the coordinate z is multiplied by your wave vector k, so it travels along z. Note that the electric field will be oscillating along the x direction. H and E are perpendicular to the direction of travel in vacuum.

6 0

3 years ago

A Cessna 150 aircraft has a lift-off speed of approximately 125 km/h. What minimum constant acceleration does this require if th

aivan3 [116]

Answer:

Part a)

$a = 3.65 m/s^2$

Part b)

$t = 9.5 s$

Part c)

$v_f = 55.1 m/s$

Explanation:

Part a)

As we know that it starts from rest and moves on runway by total distance 165 m

so we will have

$v_f^2 - v_i^2 = 2ad$

$v_f^2 - 0 = 2(a)(165)$

$v_f = 125 km/h = 34.7 m/s$

now we have

$a = 3.65 m/s^2$

Part b)

Now for take off time we will have

$v_f - v_i = at$

$34.7 - 0 = 3.65 t$

$t = 9.5 s$

Part c)

$v_f = v_i + at$

$v_f = 0 + (3.65)(15.1)$

$v_f = 55.1 m/s$

7 0

3 years ago

I need the answers to these questions

dimulka [17.4K]

The guy above looks correct

8 0

3 years ago

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

soldi70 [24.7K]

$Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}$

$GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} } \approx 1.42\cdot 10^{12}m$

3 0

4 years ago