Answer:
The units of SI: meter, kilogram, second, Kelvin
Explanation:
(a) The length of a marathon race: meter (m)
(b) The mass of an automobile
: kilogram (kg)
(c) The volume of a swimming pool
: cubic meter (m^3)
(d) The speed of an airplane
: (m/s)
(e) The density of gold
: (kg/m^3)
(f) The area of a football field
: square meter (m^2)
(g) The maximum temperature at the South Pole on April 1,1913: Kelvin (K)
Answer: A, C, E
Explanation: PLATO. all testable questions.
Colligative properties calculations are used for this type of problem. Calculations are as follows:
ΔT(boiling point) = 101.02 °C - 100.0 °C= 1.02 °C
<span>ΔT(boiling point) = (Kb)m
</span>m = 1.02 °C / 0.512 °C kg / mol
<span>m = 1.99 mol / kg
</span><span>ΔT(freezing point) = (Kf)m
</span>ΔT(freezing point) = 1.86 °C kg / mol (<span>1.99 mol / kg)
</span>ΔT(freezing point) = 3.70 <span>°C
</span>Tf - T = 3.70 <span>°C
T = -3.70 </span><span>°C</span>
Answer:
Q = 9460 Kj
Explanation:
Given data:
Mass of copper = 2kg
Latent heat of vaporization = 4730 Kj/Kg
Energy required to vaporize 2kg copper = ?
Solution:
Equation
Q= mLvap
It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg
by putting values,
Q= 2kg × 4730 Kj/Kg
Q = 9460 Kj
