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s344n2d4d5 [400]
3 years ago
8

According to ______Law, if the temperature remains constant, doubling the pressure will _______the volume of the gas.​

Chemistry
1 answer:
iren2701 [21]3 years ago
5 0

Answer: According to Boyle's Law, if the temperature remains constant, doubling the pressure will halve the volume of the gas.

Explanation:

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Consider the balanced chemical equation for the combustion of methane (CH4).
Mrac [35]
<h3>Answer:</h3>

                  89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

                                CH₄  +  2 O₂    →    CO₂  +  2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

             44 g ( 1 mol) CO₂ is produced by  =  44.8 L (2 mol) of O₂

So,

                  88 g CO₂ will be produced by  = X L of O₂

Solving for X,

                        X = (88 g × 44.8 L) ÷ 44 g

                        X = 89.6 L of O₂

5 0
3 years ago
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Why does ice float after it crystallizes? Its mass is greater than water. Its density is greater than water. Its density is less
tekilochka [14]

Ice floats after it crystallizes because ITS DENSITY IS LESS THAN THAT OF WATER.

When a quantity of water is cools down by reducing its temperature, the molecules of the water lose kinetic energy and slow down in their movement. As the water is cooling down, it is volume is expanding. When the temperature reaches zero degree Celsius, the water becomes ice. At this point, the ice can float on water because its density is less than that of water; this is as a result of the spaces that now exist in the ice structure.

7 0
3 years ago
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Which answer below correctly identifies the type of change and the explanation for the boiling of water?
lesantik [10]
Boiling Water is a physical change. When water gets to a certain temperature, it's boiling point starts. 
7 0
2 years ago
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How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)
Masteriza [31]

<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL    (Conversion factor:  1 L = 1000 mL)

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g

To calculate the heat absorbed by the water, we use the equation:

q=mc\Delta T

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(100-25)^oC=75^oC

Putting values in above equation, we get:

q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0
3 years ago
Identify an element as a metal or a non-metal according to its position in the Periodic<br> Table
Anestetic [448]

Answer:

Metals on the left of the Periodic Table.

Non-Metals on the top-right, plus Hydrogen.

4 0
2 years ago
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