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3 years ago

According to Law, if the temperature remains constant, doubling the pressure will _the volume of the gas.

1 answer:

5 0

Answer: According to Boyle's Law, if the temperature remains constant, doubling the pressure will halve the volume of the gas.

Explanation:

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3 years ago

Which of the following is a change from a more condensed to a less condensed state of matter?

forsale [732]

Well, which one of the choices is different? Freezing, solidifying, and condensing mean that the substance is getting colder. With melting, heat is being added to the substance meaning it is changing to a less condensed state of matter. The answer is melting.

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4 years ago

A 28.5 g piece of gold is heated and then allowed to cool. What is the change in temperature (°C) if the gold releases 0.106 kJ

Shkiper50 [21]

Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change). It is calculated by the expression:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= 0.106 kJ= 106 J (being 1 kJ=1000 J)
c= 25.4 $\frac{J}{molC}$
m= 28.5 g× $\frac{1 mole}{196.967 g}$ = 0.145 moles (being 196.967 g/mole the molar mass of gold)
ΔT= ?

Replacing:

106 J= 25.4 $\frac{J}{molC}$ × 0.145 moles× ΔT

Solving:

ΔT= $\frac{106 J}{25.4\frac{J}{molC}x0.145 moles}$

ΔT= 28.78 C

The change in temperature if the gold releases 0.106 kJ of heat as it cools is 28.78°C.

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2 years ago

Organic chemistry is the study of chemicals that no contain carbon true or false

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False
because carbon is very important in organic chemistry, u need to study that

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4 years ago

What mass of NH3 in grams must be used to produce 1.81 tons of HNO3 by the Ostwald process, assuming an 80.0 percent yield in ea

Alex17521 [72]

The three reactions involved in the Ostwald process for the conversion of NH3 to HNO3 are:

4NH3(g) + 5O2(g) ==> 4NO(g) + 6H2O(l) ------(1)

2NO(g) + O2(g) ==> 2NO2(g) ------------------------(2)

3NO2(g) + H2O(l) ==> 2HNO3(aq) + NO(g) ---(3)

Mass of HNO3 produced = 1.81 tons

In grams, the mass of HNO3 = 1.81*2000*453.6 = 1642032 g

Molar mass of HNO3 = 63 g/mol

Thus, # moles of HNO3 produced = 1642032/63 = 26064 moles

Based on the stoichiometry of reaction (3):

Theoretical moles of NO2 = 1.5(Moles HNO2 ) = 1.5(26064) = 39096

Assuming 80% yield:

Actual moles of NO2 = 0.8*39096 = 31277 moles

Based on the stoichiometry in reaction (2):

Theoretical moles of NO = 31277 moles

Assuming 80% yield:

Actual moles of NO = 0.8*31277 = 25022 moles

Bases on stoichiometry in reaction(3):

Moles of NH3 = 25022 moles

Assuming 80% yield:

Actual moles of NH3 required = 0.8*25022 = 20018 moles

Mass of NH3 required = 20018 moles * 17 g/mole = 340306 g = 340.31 kg

7 0

4 years ago

Read 2 more answers

According to ______Law, if the temperature remains constant, doubling the pressure will _______the volume of the gas.​

According to Law, if the temperature remains constant, doubling the pressure will _the volume of the gas.