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3 years ago

According to Law, if the temperature remains constant, doubling the pressure will _the volume of the gas.

1 answer:

5 0

Answer: According to Boyle's Law, if the temperature remains constant, doubling the pressure will halve the volume of the gas.

Explanation:

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Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp

jekas [21]

Answer:

For a: The isotopic symbol of the above atom will be $_{53}^{131}\textrm{I}$

For b: The isotopic symbol of the above atom will be $_{77}^{192}\textrm{Ir}$

For c: the isotopic symbol of the above atom will be $_{62}^{153}\textrm{Sm}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a: Iodine-131

Atomic number of iodine = 53

Mass number of iodine = 131

Symbol of iodine = I

The isotopic symbol of the above atom will be $_{53}^{131}\textrm{I}$

For b: Iridium-192

Atomic number of iridium = 77

Mass number of iridium = 192

Symbol of iridium = Ir

The isotopic symbol of the above atom will be $_{77}^{192}\textrm{Ir}$

For c: Samarium-153

Atomic number of samarium = 62

Mass number of samarium = 153

Symbol of samarium = Sm

The isotopic symbol of the above atom will be $_{62}^{153}\textrm{Sm}$

7 0

3 years ago

A different atom of iodine has a mass number of 128. What is this atoms relationship to the atom with a mass of 126

Mkey [24]

Answer:

The answer is below

Explanation:

They are isotopes. Isotopes are molecules that have the same atomic number but have different atomic mass because the number of neutrons is different.

Iodine has an atomic mass of 126 g and its atomic number is 53.

# of neutrons = 126 - 53 = 73

Its isotope has an atomic mass of 128 g its atomic number is also 53, but the number of neutrons is different.

# neutrons = 128 -53 = 75

6 0

3 years ago

Cerium (IV) ions are strong oxidizing agents in acid ic solution, oxidizing arsenio us acid to arsen ic acid accor ding to the f

kirill [66]

Answer:

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

Explanation:

Mass of $As_2O_3$ = 0.217 g

Moles of $As_2O_3=\frac{0.217 g}{198 g/mol}=0.001096 mol$

1 mole of $As_2O_3$ have 2 mole of As and 1 mole of $H_3AsO_3$ have 1 mole of As.

So, from 1 mole of $As_2O_3$ we will have 2 moles of $H_3AsO_3$

Then from 0.001096 mol of $As_2O_3$ :

$2\times 0.001096 mol=0.002192 mol$ of $H_3AsO_3$

$2Ce^{4+}(aq)+H_3AsO_3(aq)+3H_2O(l)\rightarrow 2Ce^{3+}(aq)+H_3AsO_4(aq)+2H^+(aq)$

According to reaction, 1 mole of $H_3AsO_3$ reacts with 2 mole of cerium (IV) ions,then 0.002192 mol of

$\frac{2}{1}\times 0.002192 mol=0.004384 mol$ of cerium (IV) ions.

Volume of the acidic cerium{IV) sulfate = 21.47 ml =0.02147 L

1 mL = 0.001 L

$concentration = \frac{Moles}{Volume(L)}$

$[Ce^{4+}]=\frac{0.004384 mol}{0.02147 L}=0.2042 M$

0.2042 M is the original concentration of $Ce^{4+}$ (aq) in the titrating solution.

8 0

3 years ago

If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised

alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}$

Solving for V₂ , we get:

V₂ = 15.04 mL

3 0

3 years ago

Which type of weathering is cause by plants

lilavasa [31]

B. Both mechanical and chemical waethering

7 0

3 years ago

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According to ______Law, if the temperature remains constant, doubling the pressure will _______the volume of the gas.​

According to Law, if the temperature remains constant, doubling the pressure will _the volume of the gas.