<u>Answer:</u> The equilibrium concentration of NO is 0.0034 M
<u>Explanation:</u>
We are given:
Initial moles of nitrogen gas = 0.20 moles
Initial moles of oxygen gas = 0.15 moles
Volume of container = 1.0 L
We know that:
So,
The given chemical reaction follows:
<u>Initial:</u> 0.20 0.15
<u>At eqllm:</u> 0.20-x 0.15-x 2x
The expression of follows:
We are given:
Putting values in above equation, we get:
Neglecting the negative value of 'x' because concentration cannot be negative.
So, equilibrium concentration of NO = 2 x = (2 × 0.0017) = 0.0034 M
Hence, the equilibrium concentration of NO is 0.0034 M