Answer:
5 N
Explanation:
The formula that you've to use to find the force is :
Force = Mass × Acceleration
They have already given that,
m = 2.5 kg
a = 2 ms⁻²
Let us find now.
F = m a
F = 2.5 kg × 2 ms⁻²
F = 5 N
Hope this helps you :-)
Let me know if you have any other questions :-)
Given :
A cell of e.m.f 1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.
To Find :
The current in the circuit.
Solution :
We know, resistance of the ammeter is in series with the circuit.
So, total resistance is :
R = 2.5 + 0.5 ohm
R = 3 ohm
Also, e.m.f applied is 1.5 V .
Now, by ohm's law :

Therefore, the current in the circuit is 0.5 A.
Answer:
640.59 g of NaCl.
Explanation:
Using Boiling point elevation,
ΔTb = kb * i * b
Where,
b = molality
kb = 0.52 °C kg/mole
i = van't koff factor
ΔTb = ΔTsol - ΔTsolv
= 2°C
2 = 0.52 * b
= 3.846 mol/kg.
Mass of water, solvent = 2.85 kg
Molality is the ratio of the number of moles of the solute to the mass of the solvent.
= 3.846 * 2.85
= 10.96 mol.
Mass of NaCl = molar mass * number of moles
= 58.44 * 10.96
= 640.59 g of NaCl.
Answer:
See the answers below.
Explanation:
The total power of the circuit is equal to the sum of the powers of each lamp.
![P=60+100\\P=160 [W]](https://tex.z-dn.net/?f=P%3D60%2B100%5C%5CP%3D160%20%5BW%5D)
Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

where:
P = power [W]
V = voltage [V]
I = current [amp]
![I = P/V\\I=160/240\\I=0.67 [amp]](https://tex.z-dn.net/?f=I%20%3D%20P%2FV%5C%5CI%3D160%2F240%5C%5CI%3D0.67%20%5Bamp%5D)
So this is the answer for c) I = 0.67 [amp]
We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.
a)

where:
V = voltage [V]
I = current [amp]
R = resistance [ohms]
Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

![60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]](https://tex.z-dn.net/?f=60%20%3D%20%280.67%29%5E%7B2%7D%2AR%5C%5CR_%7B60%7D%3D133.66%5Bohm%5D%20%5C%5Cand%5C%5C100%3D%280.67%29%5E%7B2%7D%20%2AR%5C%5CR_%7B100%7D%3D100%2F%280.66%5E%7B2%7D%20%29%5C%5CR_%7B100%7D%3D225%20%5Bohm%5D)
b)
The effective resistance of a series circuit is equal to the sum of the resistors connected in series.
![R = 133.66 + 225\\R = 358.67 [ohms]](https://tex.z-dn.net/?f=R%20%3D%20133.66%20%2B%20225%5C%5CR%20%3D%20358.67%20%5Bohms%5D)
$(0,,386. Sup apt g 9=6 ♂️