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DedPeter [7]
3 years ago
10

30 points + brainliest

Physics
2 answers:
Shtirlitz [24]3 years ago
5 0

Answer:

Explanation:

The answer is 138.75 kgm/s

Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt

It is given:

m = 0.25

F = 18,500 N = 18,500 kgm/s²

Δt = 0.0075 s

I = ?

I = F · Δt = 18,500 5kgm/s² * 0.0075 s = 18,500 * 0.0075 kgm/s² * s = 138.75 kgm/s

pishuonlain [190]3 years ago
4 0

Answer:B is the answer

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What is the net force on an object that has a mass of 2.5 kg and accelerates to the right at 2 m/s?
Nadya [2.5K]

Answer:

5 N

Explanation:

The formula that you've to use to find the force is :

Force = Mass × Acceleration

They have already given that,

m = 2.5 kg

a = 2 ms⁻²

Let us find now.

F = m a

F = 2.5 kg ×  2 ms⁻²

F =  5 N

Hope this helps you :-)

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5 0
2 years ago
A cell of e.M.F 1.5v and internal resistance 2.5ohm is connected in series with an ammeter of resistance 0.5ohm. Calculate the c
Tju [1.3M]

Given :

A cell of e.m.f  1.5 V and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm.

To Find :

The current in the circuit.

Solution :

We know, resistance of the ammeter is in series with the circuit.

So, total resistance is :

R = 2.5 + 0.5 ohm

R = 3 ohm

Also, e.m.f applied is 1.5 V .

Now, by ohm's law :

I = \dfrac{V}{R}\\\\I = \dfrac{1.5}{3}\\\\I = 0.5 \ A

Therefore, the current in the circuit is 0.5 A.

8 0
3 years ago
A common practice in cooking is the addition of salt to boiling water (Kb = 0.52 °C kg/mole). One of the reasons for this might
lozanna [386]

Answer:

640.59 g of NaCl.

Explanation:

Using Boiling point elevation,

ΔTb = kb * i * b

Where,

b = molality

kb = 0.52 °C kg/mole

i = van't koff factor

ΔTb = ΔTsol - ΔTsolv

= 2°C

2 = 0.52 * b

= 3.846 mol/kg.

Mass of water, solvent = 2.85 kg

Molality is the ratio of the number of moles of the solute to the mass of the solvent.

= 3.846 * 2.85

= 10.96 mol.

Mass of NaCl = molar mass * number of moles

= 58.44 * 10.96

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5 0
3 years ago
Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;
nikdorinn [45]

Answer:

See the answers below.

Explanation:

The total power of the circuit is equal to the sum of the powers of each lamp.

P=60+100\\P=160 [W]

Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

P=V*I

where:

P = power [W]

V = voltage [V]

I = current [amp]

I = P/V\\I=160/240\\I=0.67 [amp]

So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

V=I*R

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R

60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

R = 133.66 + 225\\R = 358.67 [ohms]

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