A driver takes 3.5 s to react to a complex situation while traveling at a speed of 60 mi/h. How far does the vehicle travel befo
1 answer:
Answer:
x = 93.8 m.
Explanation:
During the entire the reaction time interval, the vehicle continues moving at the same speed that it was moving, i.e., 60 mi/hr.
In order to calculate the distance in meters, travelled at that speed, it is advisable first to convert the 60 mi/hr to m/seg, as follows:
Applying the definition of average velocity, we can solve for Δx, as follows:
Δx = 26.8 m/s* 3.5 s = 93.8 m
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Answer:
shear plane angle Ф = 26.28°
shear strain 2.20
Explanation:
given data
angle = 16°
chip thickness t1 = 0.32 mm
cut yields chip thickness t2 = 0.72 mm
solution
we get here first chip thickness ratio that is
chip thickness ratio = ................. 1
put here value
chip thickness ratio =
chip thickness ratio r = 0.45
so here shear angle will be Ф
tan Ф = ............2
tan Ф =
tan Ф = 0.4938
Ф = 26.28°
and
now we get shear strain that is
shear strain r = cot Ф + tan (Ф - α ) ................3
shear strain r = cot(26.28) + tan (26.28 - 16 )
shear strain r = 2.20
Answer:
L = 46.35 m
Explanation:
GIVEN DATA
\dot m = 0.25 kg/s
D = 40 mm
P_1 = 690 kPa
P_2 = 650 kPa
T_1 = 40° = 313 K
head loss equation
where
density is constant
head is same so,
curvature is constant so
neglecting minor losses
we know is given as
therefore
V = 25.90 m/s
for T = 40 Degree,
Re = 4.16*10^5 > 2300 therefore turbulent flow
for Re =4.16*10^5 , f = 0.0134
Therefore
L = 46.35 m