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sveticcg [70]
1 year ago
7

2. Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performan

ce of recursion. In a Python file L9q2.py, write a recursive method, ackerman (m, n) which solves Ackermann's Function. Use the following logic in your function: If m = 0, then return n + 1 If n = 0, then return ackermann(m - 1, 1) Otherwise, return ackermann(m - 1, ackermann(m, n - 1)) Sample Output 1: 1. 25 Enter an integer value for m: 0 2. Enter an integer value for n: 3 3. Ackermann (0,3) = 4 Sample Output 2: 1. Enter an integer value for m: 2 2. Enter an integer value for n: 0 3. Ackermann (2,0) = 3 Sample Output 3: 1. Enter an integer value for m: 2 2. Enter an integer value for n: 3 3. Ackermann (2,3) = 9 Sample Output 4: 1. Enter an integer value for m: 3 2. Enter an integer value for n: 4 3. Ackermann (3,4) = 125
Engineering
1 answer:
oee [108]1 year ago
5 0

The python program is an implementation of the Ackermann function that a system optimizes its performance of recursion.

As per the question,

Here is an implementation of the Ackermann function in Python:

<em />

<em>def ackermann(m, n):</em>

<em>    if m == 0:</em>

<em>        return n + 1</em>

<em>    elif n == 0:</em>

<em>        return ackermann(m - 1, 1)</em>

<em>    else:</em>

<em>        return ackermann(m - 1, ackermann(m, n - 1))</em>

<em />

<em># get input values for m and n from the user</em>

<em>m = int(input("Enter an integer value for m: "))</em>

<em>n = int(input("Enter an integer value for n: "))</em>

<em />

<em># calculate and print the result of the Ackermann function</em>

<em>result = ackermann(m, n)</em>

<em>print("Ackermann ({},{}) = {}".format(m, n, result))</em>

This implementation follows the logic described in the prompt, using a recursive function to calculate the result of the Ackermann function for the given values of m and n.

To learn more about the Python Program click here:

brainly.com/question/15061326

#SPJ1

<em />

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What's the monomer? Show the structure.
ivolga24 [154]

In order to understand a monomer let´s first see the structure of a polymer. As an example, in the first figure polyethylene (or polyethene) is shown. This polymer, like every other one, is composed of many repeated subunits, these subunits are called monomer. In the second figure, polyethylene's monomer is shown.  

7 0
4 years ago
There are two identical oil tanks. The level of oil in Tank A is 12 ft and is drained at the rate of 0.5 ft/min. Tank B contains
Luba_88 [7]

Answer:

  16 minutes

Explanation:

This is an example of a class of problems in which two quantities start with different initial values and change at different rates. In such problems, the rates of change are generally ones that cause the values to converge.

The question usually asks when the values will be the same. The generic answer is, "when the difference in rates makes up the difference in initial values."

Here the tanks differ in initial fill height by 12 -8 = 4 ft. The rates of change differ by 0.5 -0.25 = 0.25 ft/min. The more filled tank is draining faster (important), so the fill heights will converge after ...

  (4 ft)/(0.25 ft/min) = 16 min

The level in the two tanks will be the same after 16 minutes.

__

<em>Additional comment</em>

The oil levels at that time will be 4 ft.

You can write two equations for height:

  y = 12 -0.5x . . . . . . . height in feet after x minutes (tank A)

  y = 8 -0.25x . . . . . .  height in feet after x minutes (tank B)

These will be equal when ...

  y = y

  12 -0.5x = 8 -0.25x

  4 = 0.25x . . . . . . . . . . add 0.5x -8

  16 = x . . . . . . . . . . . . multiply by 4 . . . . time to equal height

The graph shows when the tanks will have equal heights and when they will be drained.

4 0
2 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

6 0
3 years ago
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tankabanditka [31]
I believe the answer is D: brazing
Hope this helps you have a good night
5 0
3 years ago
As a newly hired professional engineer your an executive with the firm strongly suggests that you attend a monthly dinner party
Stolb23 [73]

Answer:

C. Decline the invitation and explain to your manager that to do otherwise is inappropriate for a registered professional engineer.

Explanation:NCEES has 3 major rules with some sub sections which helps to uphold the professional conducts of it's members.

The rule that supports this professional conduct is rule II. LICENSEE’S OBLIGATION TO EMPLOYER AND CLIENTS subsection(d)

Subsection d states that a licensee shall not reveal any information about a client,contractor or his employer to a another party except it is required by Law.

4 0
3 years ago
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