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sveticcg [70]
1 year ago
7

2. Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performan

ce of recursion. In a Python file L9q2.py, write a recursive method, ackerman (m, n) which solves Ackermann's Function. Use the following logic in your function: If m = 0, then return n + 1 If n = 0, then return ackermann(m - 1, 1) Otherwise, return ackermann(m - 1, ackermann(m, n - 1)) Sample Output 1: 1. 25 Enter an integer value for m: 0 2. Enter an integer value for n: 3 3. Ackermann (0,3) = 4 Sample Output 2: 1. Enter an integer value for m: 2 2. Enter an integer value for n: 0 3. Ackermann (2,0) = 3 Sample Output 3: 1. Enter an integer value for m: 2 2. Enter an integer value for n: 3 3. Ackermann (2,3) = 9 Sample Output 4: 1. Enter an integer value for m: 3 2. Enter an integer value for n: 4 3. Ackermann (3,4) = 125
Engineering
1 answer:
oee [108]1 year ago
5 0

The python program is an implementation of the Ackermann function that a system optimizes its performance of recursion.

As per the question,

Here is an implementation of the Ackermann function in Python:

<em />

<em>def ackermann(m, n):</em>

<em>    if m == 0:</em>

<em>        return n + 1</em>

<em>    elif n == 0:</em>

<em>        return ackermann(m - 1, 1)</em>

<em>    else:</em>

<em>        return ackermann(m - 1, ackermann(m, n - 1))</em>

<em />

<em># get input values for m and n from the user</em>

<em>m = int(input("Enter an integer value for m: "))</em>

<em>n = int(input("Enter an integer value for n: "))</em>

<em />

<em># calculate and print the result of the Ackermann function</em>

<em>result = ackermann(m, n)</em>

<em>print("Ackermann ({},{}) = {}".format(m, n, result))</em>

This implementation follows the logic described in the prompt, using a recursive function to calculate the result of the Ackermann function for the given values of m and n.

To learn more about the Python Program click here:

brainly.com/question/15061326

#SPJ1

<em />

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Explanation:

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\begin{aligned}\text { when } T=40^{\circ} C & \text { . } \\v_{40} &=0.2+\frac{0.5-0.2}{80} \times 40 \\&=0.35 V\end{aligned}

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NOTE: Refer the figure attached

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choose R2, R1 such that it will maintain required  ratio

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