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katovenus [111]
2 years ago
11

The Aluminum Electrical Conductor Handbook lists a dc resistance of 0.01558 ohm per 1000 ft at 208C and a 60-Hz resistance of 0.

0956 ohm per mile at 508C for the all-aluminum Marigold conductor, which has 61 strands and whose size is 1113 kcmil. Assuming an increase in resistance of 2% for spiraling, calculate and verify the dc resistance. Then calculate the dc resistance at 508C, and determine the percentage increase due to skin effect.
Engineering
1 answer:
Bogdan [553]2 years ago
4 0

Answer:

a) 0.01558 Ω per 1000 feet

b) 0.0923  Ω per mile

c)  3.57%

Explanation:

<u>a) Calculate and verify the DC resistance </u>

Dc resistance = R = р \frac{l}{A}

for aluminum at 20°C

р = 17 Ωcmil/ft

hence R = 17 * 1000 / ( 113000 ) = 0.01527 Ω per 1000 feet

there when there is an increase in resistance of 2% spiraling

R = 1.02 * 0.01527 = 0.01558 Ω per 1000 feet

<u>b) Calculate the DC resistance at 50°C </u>

R2 = R1 ( \frac{T+t2}{T+ t1} )

where ; R1 = 0.01558 , T = 228 , t2 = 50, t1 = 20 ( input values into equation above )

hence R2 = ( 0.01746 / 0.189 ) Ω per mile = 0.0923  Ω per mile

<u>c ) Determine the percentage increase due to skin effect </u>

AC resistance = 0.0956 ohm per mile

Hence; Increase in skin effect

= ( 0.0956  -0.0923 ) / 0.0923

=  0.0357 ≈ 3.57%

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3 years ago
A car is traveling at sea level at 78 mi/h on a 4% upgrade before the driver sees a fallen tree in the roadway 150 feet away. Th
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Answer: V = 47.7 mi/hr

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first we calculate elements of aero-dynamic resistance

Ka = p/2 * CD * A.f

p is the density of air(0.002378 slugs/ft^3) for zero altitude, CD is the drag coefficient(0.35) and A.f is the front region of the vehicle

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WE SUBSTITUTE

150 = (1.04 * 2700 / 2 * 32.2 * 0.0075) In [(0.8 * 2700 + 0.0075 *(78mil/hr * 5280ft/1min * 1hr/3600s)^2 + 0.017 * 2700 ± 2700 * 0.04) / (0.8 * 2700 + 0.0075 * V2^2 + 0.017 * 2700 ± 2700 * 0.04)]

150 = (2808/0.483) In [(2160 + 98.16 + 153.9) / ( 2160 + 0.0075V2^2 + 153.9)]

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take the e^ of both side

e^0.0258 = (2412.06) / ( 0.0075V2^2 + 2313.9)

1.0261 = (2412.06) / ( 0.0075V2^2 + 2313.9)]

(0.0075V2^2 + 2313.9) = 2412.06 / 1.0261

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V = 47.7 mi/hr

8 0
3 years ago
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