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Igoryamba
3 years ago
3

A machine can never be 100% efficient because some work is always lost due to which factor? friction gravity static input force

Physics
2 answers:
weqwewe [10]3 years ago
6 0

Explanation:

<em>Hi</em><em>,</em>

<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>friction</em><em>. </em>

<em>There</em><em> </em><em>is</em><em> </em><em>a</em><em>l</em><em>m</em><em>o</em><em>s</em><em>t</em><em> </em><em>no</em><em> </em><em>machine</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>not</em><em> </em><em>affected</em><em> </em><em>by</em><em> </em><em>friction</em><em>.</em><em> </em><em>It</em><em> </em><em>losts</em><em> </em><em>some</em><em> </em><em>work</em><em> </em><em>due</em><em> </em><em>to</em><em> </em><em>friction</em><em> </em><em>while</em><em> </em><em>working</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

Furkat [3]3 years ago
5 0

Answer:

friction

Explanation:

the other options dont effect efficiency

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3 years ago
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Answer:

positive plate

E = 5.764 KV / m

W = 490eV or 7.85 * 10^-17 J

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Explanation:

part a

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Answer: The positive plate is at higher potential because of convention.

part b

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Answer: Electric Field between the plates E = 5.764 KV / m

part c

Work done by electric field

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Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J

part d

Potential Energy of an electron gained:

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E_p =  9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)

E_p = 4.74 *10^(-12) eV

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Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.

part e

Kinetic Energy of an electron gained:

W - E_p = E_k

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3 years ago
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7 0
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