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julia-pushkina [17]
2 years ago
10

I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?

Physics
1 answer:
storchak [24]2 years ago
5 0

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

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I need the answer please help
timurjin [86]

Answer:

A) Inertia

Explanation:

Inertia is why objects tend to resist changes in their motion. Like a rolling ball will keep rolling unless we try to add friction to it, which then would stop the ball.

3 0
2 years ago
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State two environmental problems caused by coal fired power stations
Julli [10]

Answer:

Air pollution and water pollution.

Explanation:

The burning of coal causes air pollution, and coal fired power stations dump waste in large bodies of water.

6 0
3 years ago
Mark has brown hair. His wife, Maggie, also has brown hair. Mark and Maggie have four children. Three children have brown hair,
alekssr [168]
I would say B.) the blonde hair was a result of the expression of a recessive gene. - the dominate gene is brown hair and the recessive gene is blonde hair...hope this helps
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3 years ago
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Heat likes to remain <br> ONMFRIU ← Whats that unscrambled?
OlgaM077 [116]
<span>So the question is how does heat prefer to remain and to unscramble the letters ONMFRIU. The unscrambled letters mean: UNIFORM. The heat likes to remain uniform because thermodynamic systems always tend to reach thermal equilybrium after some period of time that is specific for each system. </span>
5 0
3 years ago
In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e
Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_1-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_3)}{Q_1}}

also,

\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}

or

\frac{T_3}{T_1}=\frac{Q_3}{Q_1}

thus,

\eta=1-\frac{(T_3)}{T_1}}

thus,

\eta=1-\frac{(240\ K)}{500\ K}}

or

\eta=0.52

or

Efficiency = 52%

8 0
3 years ago
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