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3 years ago

I drove from Oklahoma to California (1452.9 miles) in 23 hours? What was my average speed?

Physics

1 answer:

storchak [24]3 years ago

5 0

Answer:

63 miles per hour

Explanation:

you just divide miles and hours to get your average speed

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During an experiment, a scientist places a heat lamp above a bowl of water and uses the lamp to heat up the water. How does heat

alexandr402 [8]

Answer:

radiation

Explanation:

6 0

3 years ago

Read 2 more answers

What is the name of the small early planets, which formed through gravitational attraction reaching sizes of a few miles to even

Svetradugi [14.3K]

Answer:

Planetesimals (Ex, Mercury, Venus , Mars & Earth)

Explanation:

They are known as Planetesimals , They are small in size and have rocky surface. The examples of Planetesimals are Mercury, Venus Mars and Earth.

They are small early planets , which also has gravitational attraction.

Thanks

6 0

4 years ago

What is the momentum of a vehicle that has a mass of 1500kg and a velocity of 15m/s? (don't forget the unit is kg*m/s, and needs

alex41 [277]

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 1500 × 15

We have the final answer as

Hope this helps you

4 0

3 years ago

State laws of magnetism

kykrilka [37]

Explanation:

A basic law of magnetism is that unlike poles attract each other. Two bar magnets can illustrate this. ... A pole of the second is brought, in turn, near each of the two ends of the hanging magnet.

Second Law of Magnetism

The force is in direct proportion to the product of the forces of the pole. The force exists in inverse proportion to the square of the middle distance between the poles. The force is dependent on the specific medium in which the magnets are placed.

4 0

3 years ago

Hi.

docker41 [41]

<h3>Answer :</h3>

Let the final temperature be "T".

For the piece of copper :

mass, $\sf{m_c=40\ g.}$

specific heat capacity, $\sf{c_c=0.4\ J\,g^{-1}\,K^{-1}.}$

initial temperature, $\sf{T_c=200^{\circ}C.}$

Then the heat of copper :

$\sf{\dashrightarrow Q_c=m_cc_c\,\Delta\!T_c}$

$\sf{\dashrightarrow Q_c =16(T-200)\ J}$

For copper calorimeter :

mass, $\sf{m_{cc} =60\ g.}$

specific heat capacity, $\sf{c_{cc} =0.4\ J\,g^{-1}\,K^{-1}.}$

initial temperature, $\sf{T_{cc} =25^{\circ}C.}$

Then the heat of copper calorimeter :

$\sf{\dashrightarrow Q_{cc} =m_{cc}c_{cc}\,\Delta\!T_{cc}}$

$\sf{\dashrightarrow Q_{cc} =24(T-25)\ J}$

For water :

mass, $\sf{m_w=50\ g. }$

specific heat capacity, $\sf{c_w= 4.2\ J\,g^{-1}\,K^{-1}.}$

initial temperature, $\sf{T_w=25^{\circ}C.}$

Then heat of water :

$\sf{\dashrightarrow Q_w=m_wc_w\,\Delta\!T_w}$

$\sf{\dashrightarrow Q_w=210(T-25)\ J}$

By energy conservation, the sum of all these energies should be zero as there were no heat energy change before the process, i.e.,

$\sf{\dashrightarrow Q_c+Q_{cc}+Q_w=0}$

$\sf{\dashrightarrow16(T-200)+24(T-25)+210(T-25)=0}$

$\sf{\dashrightarrow 250T- 9050=0}$

$\sf{\dashrightarrow T=36.2^{\circ}C}$

$\large \underline{\underline{\boxed{\sf T=36.2^{\circ}C}}}$

<u>____________________________</u>

[Note: in case of considering temperature difference it's not required to convert the temperatures from $\sf{^{\circ}C}$ to K or K to $\sf{^{\circ}C}$ .]

7 0

3 years ago