The given question is incomplete. The complete question is:
Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.
Answer: 0.0484 g
Explanation:
where Q= quantity of electricity in coloumbs
I = current in amperes = 0.920 A
t= time in seconds = 47.0 sec
96500 Coloumb of electricity electrolyzes 1 mole of Ag
43.24 C of electricity deposits =
of Ag
Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g
Answer is: same orbital, but have different spin directions.
The principal quantum number (n) is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
For principal quantum number n=2:
1) azimuthal quantum number (l) can be l = 0...n-1:
l = 0, 1.
The azimuthal quantum number determines its orbital angular momentum and describes the shape of the orbital.
2) magnetic quantum number (ml) can be ml = -l...+l.
ml = -1, 0,+1.
Magnetic quantum number specify orientation of electrons in magnetic field and number of electron states (orbitals) in subshells.
3) the spin quantum number (ms), is the spin of the electron.
ms = +1/2, -1/2.
Answer:
No, it won't. Because water is made up of two atoms of hydrogen and an atom of oxygen (the composition of water).So now do you understand? Text me if you do/don't for more explanation. Thanks for asking
