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Bond [772]
3 years ago
13

What is the total energy needed to boil 255 grams of water, given that the

Chemistry
1 answer:
nexus9112 [7]3 years ago
3 0

Answer:

  • <u>575,000 J</u>

Explanation:

<u>1) Convert the mass of water into number of moles</u>

  • Molar mass of water: 18.015 g/mol

  • Number of moles, n = mass in grams / molar mass

        n = 255 g / 18.015 g/mol = 14.15 mol

<u>2) Use the formula E = n × ΔH vap</u>

This is, you have to multiply the molar ΔH vaporization by the number of moles to find the total energy to boil the given amount of water.

  • E = 14.15 mol × 40,650 J/mol = 575,395.5 J

<u>3) Round to the correct number of significant figures.</u>

The mass of water is the measurement with the least number of significant figures (3), so you must report the answer with 3 significant figures,

  • E = 575,000 J ← answer
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Typically, the oxidation state of Pb in lead nitrate tend to be +2. In other words, Pb in lead nitrate tends to exist as \text{Pb}^{2+} ions. The formula for a nitrate ion is {\text{NO}_3}^{-}. The charge on each of the nitrate ion is -1. The charge on the two ions should balance. As a result, each \text{Pb}^{2+} ion in lead nitrate would pair up with two {\text{NO}_3}^{-} ions. The formula for lead nitrate will be \text{Pb}({\text{NO}_3})_2. Each formula unit of lead nitrate will contain one \text{Pb}^{2+} ion and two {\text{NO}_3}^{-} ions.

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