The acceleration of the wagon along the ground is 3.6 m/s².
To solve the problem above, we need to use the formula of acceleration as related to force and mass.
Acceleration: This can be defined as the rate of change of velocity.
⇒ Formula:
- Fcos∅ = ma................. Equation 1
⇒ Where:
- F = Force
- ∅ = angle above the horizontal
- m = mass of the wagon
- a = acceleration of the wagon
⇒ make a the subject of equation 1
- a = Fcos∅/m..................... Equation 2
From the question,
⇒ Given:
⇒ Substitute these values into equation 2
- a = 44(cos35°)/10
- a = 44(0.8191)/10
- a = 3.6 m/s²
Hence, The acceleration of the wagon along the ground is 3.6 m/s²
Learn more about acceleration here: brainly.com/question/9408577
The b<span>ottom one because it has longer wavelengths and because the bottom ones has 3 wavelengths</span>
Answer:
Diffraction
Explanation:
Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.
Answer:
DETAILS IN THE QUESTION INSUFFICIENT TO ANSWER
Explanation:
Assuming the liquid to be water ,
the density
of water is :
Buoyant force exerted by a liquid on an object with
of it's volume immersed is :
![F_{B}=V_{imm}*d_{l}*g](https://tex.z-dn.net/?f=F_%7BB%7D%3DV_%7Bimm%7D%2Ad_%7Bl%7D%2Ag)
where ,
is the buoyant force
is the density of the liquid
is the acceleration due to gravity
Thus at equilibrium:
![m_{brass}*g=V_{imm}*d_{l}*g\\m_{brass}=V_{imm}*d_{l}\\54=V_{imm}*1\\V_{imm}=54cm^{3}](https://tex.z-dn.net/?f=m_%7Bbrass%7D%2Ag%3DV_%7Bimm%7D%2Ad_%7Bl%7D%2Ag%5C%5Cm_%7Bbrass%7D%3DV_%7Bimm%7D%2Ad_%7Bl%7D%5C%5C54%3DV_%7Bimm%7D%2A1%5C%5CV_%7Bimm%7D%3D54cm%5E%7B3%7D)
from these , we get the density of brass to be ![1gcm^{-3}](https://tex.z-dn.net/?f=1gcm%5E%7B-3%7D)
which is not possible