Answer:
The final velocity is 28.14 m/s
Yes the angle of projection matters
Explanation:
Given;
initial velocity of the water balloon, u = 20 m/s
height of the building, h = 20 m
let the final speed of the ball when it hits the ground = v
The final speed is calculated as follows;
v² = u² + 2gh
v² = (20)² + 2(9.8)(20)
v² = 400 + 392
v² = 792
v = √792
v = 28.14 m/s
Yes the angle matters, if the balloon had been dropped at a certain angle, the final velocity would have been estimated using the following formula;

where;
θ is the angle of projection, which accounts for the vertical component of the velocity.
funny, actually, i'm a hydraulic, and pneumatic cylinder, pump, and line system mechanic, and the answer is pressure.... pressure builds up from the hydraulic pump, and then transfers through hoses to extend, and contract the cylinders by filling them with hydraulic fluid, and vice versa for contracting them.
hope this helps!
Answer:
27.95[kW*min]
Explanation:
We must remember that the power can be determined by the product of the current by the voltage.

where:
P = power [W]
V = voltage [volt]
I = amperage [Amp]
Now replacing:
![P=110*8.47\\P=931.7[W]](https://tex.z-dn.net/?f=P%3D110%2A8.47%5C%5CP%3D931.7%5BW%5D)
Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]
![Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min]](https://tex.z-dn.net/?f=Energy%20%3D%20931.7%5BkW%5D%2A30%5Bdays%5D%2A10%5B%5Cfrac%7Bmin%7D%7B1day%7D%20%5D%3D279510%5BW%2Amin%5Dor%2027.95%5BkW%2Amin%5D)