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Minchanka [31]
3 years ago
14

Imagine that you have a 5.50 l gas tank and a 4.00 l gas tank. you need to fill one tank with oxygen and the other with acetylen

e to use in conjunction with your welding torch. if you fill the larger tank with oxygen to a pressure of 145 atm , to what pressure should you fill the acetylene tank to ensure that you run out of each gas at the same time? assume ideal behavior for all gases.
Physics
1 answer:
miv72 [106K]3 years ago
5 0

To solve this problem, we must first assume that the two gases acetylene and oxygen to act like an ideal gas so that we can use the ideal gas equation:

P V = n R T

where,

P is the pressure inside the tank, V is the volume of the tank, n is the number of moles of gas, R is the universal gas constant and T is the absolute temperature

 

Now to ensure that we run out of each gas at the same time, we must also assume that n and T are equal for both gases, therefore:

P V = constant

 

So now we can equate the PV for the two gases to find for the pressure of the other tank:

145 atm (5.50 L) = P (4.00 L)

P = 199.375 atm

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q=2.997\times 10^{-4}C

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Explanation:

We are given that

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100q=0.57\times 10^{-3}+29.4\times 10^{-3}=29.97\times 10^{-3}

q=\frac{29.97\times 10^{-3}}{100}

q=2.997\times 10^{-4}C

Sign of charge =Negative

Because electric force acting  in opposite direction of electric field therefore,charge on penny will be negative.

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