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svet-max [94.6K]

3 years ago

6

How should the goals of a beginner differ from someone who is more advanced?

1 answer:

nevsk [136]3 years ago

6 0

Hi!

A beginner is less skilled than someone who is more advanced, and has, in most cases, less experience.

Therefore, if they each set realistic goals for their skill levels, a beginner will have less, adventurous (for lack of a better word) goals because the beginner knows they can achieve less, while an advanced person would set higher goals that are more difficult to achieve, but realistic for themselves.

Hope this helped!

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Starting from rest, a disk takes 8 revolutions to reach an angular velocity ω at constant angular acceleration. how many additio

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W^2 = 2 A 8 where A is the angular acceleration.
(3w)^2 = 2 A R where R is the number of revolutions.
Note that you are asked for the additional revolutions.

4 0

4 years ago

Radon-222 ( 222/86 Rn) is a radioactive gas with a half-life of 3.82 days. A gas sample contains 4.1 e 8 radon atoms initially.

kow [346]

Answer :

(a) The number of radon atoms will remain after 12 days is, $4.67\times 10^7$

(b) The number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

Explanation :

<u>For part (a) :</u>

Half-life = 3.82 days

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{3.82\text{ days}}$

$k=1.81\times 10^{-1}\text{ days}^{-1}$

Now we have to calculate the number of radon atoms will remain after 12 days.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.81\times 10^{-1}\text{ days}^{-1}$

t = time passed by the sample = 12 days

a = initially number of radon atoms = $4.1\times 10^8$

a - x = number of radon atoms left = ?

Now put all the given values in above equation, we get

$12=\frac{2.303}{1.81\times 10^{-1}}\log\frac{4.1\times 10^8}{a-x}$

$a-x=4.67\times 10^7$

Thus, the number of radon atoms will remain after 12 days is, $4.67\times 10^7$

<u>For part (b) :</u>

Now we have to calculate the number of radon nuclei will have decayed by this time.

The number of radon nuclei have decayed = Initial number of radon atoms - Number of radon atoms left

The number of radon nuclei have decayed = $(4.1\times 10^8)-(4.67\times 10^7)$

The number of radon nuclei have decayed = $3.6\times 10^8$

Thus, the number of radon nuclei have decayed by this time will be, $3.6\times 10^8$

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Answer:

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