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kiruha [24]
3 years ago
10

Anyone Free can help me with this question please ?

Chemistry
1 answer:
ElenaW [278]3 years ago
5 0

Answer:

68

Explanation:

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One of the reasons that stars are so large is because _____.
ValentinkaMS [17]

Answer:

They are composed of hydrogen and helium

4 0
3 years ago
Read 2 more answers
A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦c. How many moles of helium will there be in the balloon at st
satela [25.4K]

Answer:

  • There will be 1.23 moles of helium in the balloon at STP

Explanation:

1) <u>Initial conditions of the helium gas</u>:

  • V = 20.0 liter
  • p = 1.50 atm
  • T = 25.0 °C = 25.0 + 273.15 K = 298.15 K

2) <u>Ideal gas equation</u>:

  • pV = n RT
  • p, V, and T are given above
  • R is the Universal constant = 0.0821 atm-liter / ( K - mol)
  • n is the unknown number of moles

3) <u>Solve for n</u>:

  • n = pV / (RT) =
  • n = 1.50 atm × 20.0 liter / (0.0821 atm-liter /k -mol ×298.15K)
  • n = 1.23 mol

4) <u>At STP:</u>

  • STP stands for standard pressure and temperature.
  • The amount (number of moles) of the gas will not change because the change of pressure and temperature, so the number of moles reamain the same: 1.23 mol.
8 0
3 years ago
A student has a solution of sodium nitrate and believes it is saturated. Which statement provides the best evidence that the sol
zheka24 [161]

It is easiest to tell if a solution is saturated if there is residue on the bottom. If it crystallized, the solution is saturated. If it is a supersaturated solution, there will not be crystallization unless more of the solute is added, at which point all of it will crystallize.

6 0
3 years ago
Amphetamine (C9H13N) is a weak base with a pKb of 4.2.
QveST [7]

Weak base: [OH⁻] = √Kb.C

pKb = 4.2

\tt Kb=10^{-4.2}

c = concentration

MM Amphetamine (C9H13N) = 135.21 g/mol

c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59  x 10⁻³ mol/L

\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}

pOH = 4 - log 3.17

pH = 14 - (4 - log 3.17)

pH = 10 + log 3.17 = 10.50

4 0
2 years ago
How many millimeters of 1.25 M Copper(2) sulfate, CuSO4, will contain 55.75g CuSo4
Shkiper50 [21]

Answer:

280 mL

Explanation:

Given data:

Mass of CuSO₄ = 55.75 g

Molarity of CuSO₄ = 1.25 M

Volume of CuSO₄ = ?

Solution:

First of all we will calculate the number of moles.

Number of moles:

Number of moles = mass / molar mass

Number of moles = 55.75 g/ 159.6 g/mol

Number of moles = 0.35 mol

Volume of CuSO₄:

Molarity = number of moles / volume in litter

1.25 M = 0.35 mol / volume in litter

Volume in litter = 0.35 mol / 1.25 M

Volume in litter = 0.28 L

Volume in milliliter:

0.28 L × 1000 mL/ 1 L = 280 mL

8 0
3 years ago
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