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3 years ago

Andrew is riding his bike is riding in a circle that has a radius of 10 m. He keeps

Physics

1 answer:

Dmitrij [34]3 years ago

8 0

The acceleration that Andrew experience during his ride is 3.6m/s²

The formula for calculating centripetal acceleration is expressed as:

a = v²/r

v is the speed

r is the radius

Given the following expression

v = 6m/s

r = 10m

Substitute the given parameters into the formula

a = 6²/10

a = 36/10

a = 3.6m/s²

Hence the acceleration that Andrew experience during his ride is 3.6m/s²

Learn more here: brainly.com/question/1268866

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Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maxi

Korolek [52]

Answer:

2C charge will flow from ground and cloud

Explanation:

We have given rate rate of flow of charge $\frac{dq}{dt}=20000C/sec$

Time is given as $t=100\mu sec=100\times 10^{-6}=10^{-4}sec$

WE have to find the how much charge flows between the ground and cloud in this time

So the charge flow is given by $\frac{dq}{dt}\times t=20000C/sec\times 10^{-4}=2C$

So 2C charge will flow from ground and cloud

8 0

3 years ago

A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.

Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

k x = m g

$k = \dfrac{mg}{x}$

$k = \dfrac{6.4 \times 9.8}{0.28}$

k = 224 N/m

b) $f = \dfrac{\omega}{2\pi}$

$\omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

$f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}$

$f =0.94\ Hz$

c) $v_b = -v cos \omega t$

$v_b = -5.1 \times cos (5.92 \times 0.42)$

$v_b = 4.04\ m/s$

d) $a_{max} = v \omega$

$a_{max} = 4.04 \times 5.92$

$a_{max} =23.94\ m/s^2$

e) $Y =- A sin (\omega t)$

$A = \dfrac{v}{\omega}$

$A = \dfrac{4.04}{5.92}$

A = 0.682 m

$Y =- 0.682 \times sin (5.92 \times 0.42)$

$Y =- 0.42$

Force = $m \omega^2 |Y|$

= $6.4 \times 5.92^2\times 0.42$

F = 94.20 N

4 0

3 years ago

To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a

irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

= 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

W = F x S joules

Substituting the values in the above equation

W = 1.5 x 10⁶ x 355 · sin θ

= 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J

6 0

3 years ago

A helicopter flying horizontally at a height H with a speed v0needs to drop a supply capsule to a point P . Assume the capsule h

irinina [24]

L = V0 x t
L = V0 x (2H/g)^1/2

7 0

3 years ago

Which of the following is a result of reduced levels of red blood cells and elevated levels of white blood cells in the body?

Tju [1.3M]

The cells that circulate in the bloodstream are generally divided into three types, white blood cells.

8 0

3 years ago