Question

A settling tank with 50 foot diameter and a SWD of 9 feet treats

Answer 1

Answer:

Detention time will be 9 days

Explanation:

We have given diameter of setting tank d = 50 feet

Radius of setting tank $r=\frac{d}{2}=\frac{9}{2}=25 feet$

SWD = 9 FEET

Area $A=\pi r^2=3.14\times 25^2=1962.5ft^2$

So volume $V = area\times SWD=1962.5\times 9=17671.5ft^3$

We have given flow Q = 15000 gpd

So Q= 15000×0.13368 =2005.22 $ft^3$ per day

Detention time is given by $=\frac{volume}{Q}=\frac{17671.5}{2005.22}=9days$

So detention time will be 9 days