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3 years ago

A settling tank with 50 foot diameter and a SWD of 9 feet treats

Engineering

1 answer:

guajiro [1.7K]3 years ago

4 0

Answer:

Detention time will be 9 days

Explanation:

We have given diameter of setting tank d = 50 feet

Radius of setting tank $r=\frac{d}{2}=\frac{9}{2}=25 feet$

SWD = 9 FEET

Area $A=\pi r^2=3.14\times 25^2=1962.5ft^2$

So volume $V = area\times SWD=1962.5\times 9=17671.5ft^3$

We have given flow Q = 15000 gpd

So Q= 15000×0.13368 =2005.22 $ft^3$ per day

Detention time is given by $=\frac{volume}{Q}=\frac{17671.5}{2005.22}=9days$

So detention time will be 9 days

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2 years ago

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3 years ago

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Answer:

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Explanation:

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3 years ago

The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to th

Ilia_Sergeevich [38]

Answer:

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Pressure change at probe tip

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Explanation:

Question is incomplete

The air velocity in the duct of a heating system is to be measured by a Pitot-static probe inserted into the duct parallel to the flow. If the differential height between the water columns connected to the two outlets of the probe is 0.126m, determine (a) the flow velocity and (b) the pressure rise at the tip of the probe. The air temperature and pressure in the duct are 352k and 98 kPa, respectively

solution

In this question, we are asked to calculate the flow velocity and the pressure rise at the tip of probe

please check attachment for complete solution and step by step explanation