The odometer of an automobile measures the distance travelled by the vehicle. the car(b) is moving faster.
This can be explained as follows:
In order to compare the speed of both the vehicles and determine which one is moving faster, the speed of both the vehicles should be represented by the same unit.
Speed of scooter = 300 m/min
Converting this to km/hr,
Distance travelled by the scooter in 1 min= 300 m
Therefore, distance travelled by the scooter in 60min( or 1 hr ) = 18000m = 18 km
Speed of the car= 36 km/hr
Since the car travels a greater distance in 1 hr , we can say that it is moving faster.
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Answer:
P₂ = 370 kPa
Explanation:
Boyle's law: States that the volume of a given mass of gas is inversely proportional to its pressure provided the temperature remains constant. It can be expressed mathematically as,
P₁V₁ = P₂V₂................ Equation 1
Where P₁ = Initial Pressure, V₁ = Initial volume, P₂ = Final Pressure, V₂ = Final Volume.
Making P₂ The subject of the equation above,
P₂ = P₁V₁/V₂..................... equation 2
Substituting these vaues into equation 2,
Where P₁ = 163 kPa = 163000 pa, V₁ = 10 L, V₂ = 4.4 L.
P₂ = 163000(10)/4.4
P₂ = 370454.55 Pa
P₂ = 370000 Pa
P₂ = 370 kPa To 3 significant figure.
Therefore Final pressure = 370 kPa
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
Answer here
The displacement of the cars is somewhere near 0 miles since they virtually finish where they started. Yet the successful cars have covered a distance of 500 miles
The fraction of the kinetic energy of the ball lost during the collision is 
.
The given parameters;
- <em>initial speed of the ball, = vi</em>
- <em>final momentum of the ball, Pf = ¹/₃Pi</em>
The initial and final momentum of the ball is calculated as;
The initial and final kinetic energy of the ball is calculated as;
The change in the kinetic energy is calculated as;
Thus, the fraction of the kinetic energy of the ball lost during the collision is .
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