Answer:
C. An ion with a +2 charge
Explanation:
I guess
-- loud sounds
-- bright lights
-- strong radio signals
-- Slinkies that can pinch you painfully
-- a tsunami in the ocean
-- earthquakes above Richter 5 or 6
Answer:
51.94 ft/s²
257.63 ft/s
Explanation:
t = Time taken = 4 s
u = Initial velocity = 34 mi/h
v = Final velocity
s = Displacement = 615 ft
a = Acceleration
Converting velocity to ft/s
![34\ mi/h=\frac{34\times 5280}{3600}=49.87\ ft/s](https://tex.z-dn.net/?f=34%5C%20mi%2Fh%3D%5Cfrac%7B34%5Ctimes%205280%7D%7B3600%7D%3D49.87%5C%20ft%2Fs)
Equation of motion
![s=ut+\frac{1}{2}at^2\\\Rightarrow a=2\frac{s-ut}{t^2}\\\Rightarrow a=2\left(\frac{615-49.87\times 4}{4^2}\right)\\\Rightarrow a=51.94\ ft/s^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20a%3D2%5Cfrac%7Bs-ut%7D%7Bt%5E2%7D%5C%5C%5CRightarrow%20a%3D2%5Cleft%28%5Cfrac%7B615-49.87%5Ctimes%204%7D%7B4%5E2%7D%5Cright%29%5C%5C%5CRightarrow%20a%3D51.94%5C%20ft%2Fs%5E2)
Acceleration is 51.94 ft/s²
![v=u+at\\\Rightarrow v=49.87+51.94\times 4\\\Rightarrow v=257.63\ ft/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D49.87%2B51.94%5Ctimes%204%5C%5C%5CRightarrow%20v%3D257.63%5C%20ft%2Fs)
Final velocity at this time is 257.63 ft/s
To determine the height of the object given the time, we simply use the given relation between height and time in the problem statement. It is given as:
h = -16t^2 + 127t
We substitute 55 seconds to t and obtain,
h = -16(55)^2 + 127(55)
h = - 41415
On Earth, a cannonball with a mass of 20 kg would weigh 196 Newtons.
With the formula F=mg, where F is the weight in Newtons, m is the mass, and g is the acceleration due to gravity on the Earth which is 9.8m/s^2.
F=20kg x 9.8m/s^2= 196 Newtons
BUT on the moon, acceleration due to gravity is 1.6 m/s^2,
so F=mg=20kgx1.6m/s^2= 32 N