Question :
If a body acquires a charge of -0.02 C, has it gained or lost electrons? Many?
Solution :
We know, charge gained is shown by negative sign.
Since, charged acquired is given as -0.02 C .
Therefore, it is body has gained electrons.
Now, number of electrons is given by :
![n = \dfrac{net\ charge}{charge \ on \ one \ electron}\\\\n = \dfrac{-0.02}{-1.60 \times 10^{-19}}\\\\n = 1.25\times 10^{17}](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7Bnet%5C%20charge%7D%7Bcharge%20%5C%20%20on%20%5C%20one%20%5C%20%20electron%7D%5C%5C%5C%5Cn%20%3D%20%5Cdfrac%7B-0.02%7D%7B-1.60%20%5Ctimes%2010%5E%7B-19%7D%7D%5C%5C%5C%5Cn%20%3D%201.25%5Ctimes%2010%5E%7B17%7D)
Hence, this is the required solution.
<span>1. Kuiper Belt object is made of frozen is made of frozen gas, ice, and dust that orbits in the outermost reaches of the solar system. Kuiper belt is a region which is filled with icy gaz bodies. Its structure is almost the same as the asteroid belt between Mars and Jupiter. Pluto, Makemake, Haumea are the officially recognized planets which are located in this region.
2. In my opinion, the most suitable option is: 3) The planets formed at the center of a collapsing spinning cloud of gas and dust. According to theory of solar system formation, the solar system appeared after a supernova (star explosion). A cloud of gas and dust was collapsed, and it caused a formation of a solar nebula.
</span>
Answer:
<u><em>Circular motion requires a net inward or "centripetal" force. Without a net centripetal force, an object cannot travel in circular motion. In fact, if the forces are balanced, then an object in motion continues in motion in a straight line at constant speed.</em></u>
Explanation:
Answer:
Momentum, p = 23250 kg m/s
Explanation:
Given that
Mass of a car, m = 1550 kg
Speed pf car, v = 15 m/s
We need to find the momentum of the car. The formula for the momentum of an object is given by :
p = mv
Substituting all the values in the above formula
p = 1550 kg × 15 m/s
p = 23250 kg m/s
So, the momentum of the car is 23250 kg m/s.