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Serhud [2]
3 years ago
8

One writer, a group of students measured snowfall totals at their school. This chart shows how many inches of snow the students

measured each month. How much snowfall did they receive in January and February combined?
January 3.4
February 8.4

Mathematics
1 answer:
tangare [24]3 years ago
4 0

The correct answer is 20.7 inches of snow

Explanation:

The chart registers the total of snowfall at the school, in this, you can observe the total of snow in December was 3.4 inches, while in January the total was 12.3 and in February it was 8.4. Additionally, if you want to know the total during January and February combined the correct process is to add the two numbers. This means 12.3 inches (January) + 8.4 inches (February) = 20. 7 inches (Total in January and February.) Thus, the answer is 20.7 inches of snow.

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What is the domain of this relation?<br><br> {(5,6), (5,3), (5,1), (5,0), (5,-6), (5,-10)}
mr Goodwill [35]

Answer:

5

Step-by-step explanation:

All of the x values are 5, so the domain is 5

7 0
2 years ago
4x+3y how to solve this question and why is it such a small question
Law Incorporation [45]
I need help on that do you know the answer
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4 years ago
Nth term of this sequence 1, 10, 19, 28
mestny [16]

Answer:

The nth term of the sequence is

<h2>9n - 8</h2>

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1

d = 10 - 1 = 9 or 19 - 10 = 9 or 28 - 19 = 9

So the nth term of the sequence is

A(n) = 1 + (n - 1)9

= 1 + 9n - 9

= 9n - 8

<h3>A(n) = 9n - 8</h3>

Hope this helps you

3 0
3 years ago
Find the equation of the tangent line. y=(x^2+x-2)^2 at (-1,4)​
Keith_Richards [23]

Compute the derivative of <em>y</em> = (<em>x</em>² + <em>x</em> - 2)² using the chain rule:

d<em>y</em>/d<em>x</em> = 2 (<em>x</em>² + <em>x</em> - 2) d/d<em>x</em> [<em>x</em>² + <em>x</em> - 2]

d<em>y</em>/d<em>x</em> = 2 (<em>x</em>² + <em>x</em> - 2) (2<em>x</em> + 1)

Evaluate the derivative at <em>x</em> = -1 :

d<em>y</em>/d<em>x</em> (-1) = 2 ((-1)² + (-1) - 2) (2 (-1) + 1) = 4

This is the slope of the tangent line to the function at (-1, 4).

Use the point-slope formula to get the equation for the tangent line:

<em>y</em> - 4 = 4 (<em>x</em> - (-1))   →   <em>y</em> = 4<em>x</em> + 8

6 0
3 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}&#10;solutions&graphs&slopes\\&#10;----&----&----\\&#10;\textit{exactly one}&&#10;\begin{array}{llll}&#10;\textit{the two lines intersect}\\&#10;\textit{at one point}&#10;\end{array}&\textit{different slopes}\\\\&#10;infinitely\quad many&&#10;\begin{array}{llll}&#10;\textit{the two lines coincide}\\&#10;\textit{one is right on top}\\&#10;\textit{ of the other}&#10;\end{array}&&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{equal y-intercepts}&#10;\end{array}&#10;\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &&#10;\begin{array}{llll}&#10;\textit{equal slopes}\\&#10;\textit{different y-intercepts}&#10;\end{array}&#10;\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
4 years ago
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