The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
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Answer:
evaporation to condensation to precipitation.
Answer:
Explanation:
Given
mass of car 
Vertical displacement 
spring constant 
Considering we need to find out compression in the spring when it reaches to ground
Here Gravitational potential Energy is converted to kinetic energy which finally converts to Elastic Potential Energy
suppose x is the compression in spring
Potential Energy=mgh
Elastic potential energy

-- Charges with the same sign repel each other.
-- Charges with different signs attract each other.
-- This is called the "electrostatic force".
-- There's another set of forces called "magnetic forces", but
-- there's no such thing as "electromagnetic force".
Answer:

Explanation:
Given:
electric field, 
charge, 
initial position coordinates, 
final position coordinates, 
We find the distance through which the charge has been moved:

Where we have (x1,y1) & (x2,y2) as the initial and final coordinates of the points.


Now we need the angle through which displacement is made with respect to the direction of electric field.

![\theta= tan^{-1}[\frac{76-(-131)}{107-(-81)} ]](https://tex.z-dn.net/?f=%5Ctheta%3D%20tan%5E%7B-1%7D%5B%5Cfrac%7B76-%28-131%29%7D%7B107-%28-81%29%7D%20%5D)

Now from the relation between the change in potential difference:



∵The change in voltage is defined as the work done per unit charge.
∴

Putting the respective values

