Answer:
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
Explanation:
A. The procedure used did not include MEP recordings prior to each task.
Not true, is not a requisite record MEP prior to the task to evaluate the variable of interest on this case.
B. MEP amplitudes in an individual are typically highly consistent.
The Motor evoked potentials (MEP) "are electrical signals recorded from neural tissue or muscle after activation of central motor pathways". But on this case that's a technical aspect related to the topic and this not would be the reason why we need to withhold the presentation
C. The motor tasks performed in the experiment were too simple.
On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.
D. The six different conditions were run in random order.
That's not true the student are not analyzing 6 different conditions, just 2.
Answer:
True
Explanation:
You pay back what you owe for what youve purchased
Answer:
While the water falls v increases and h decreases, so the kinetic energy increases and the gravitational potential energy decreases, and this happens in a way that the total energy is always the same. (If there is no friction)
Explanation:
Answer:
a) total moment of inertia is 1359.05 kg m^2
b) angular acceleratio is 0.854rad/sec^2
Explanation:
Given data:
m1=6.9 kg
L=4.88 m
m2=34.5 kg
R=1.22 m
we klnow that moment of inertia for rod is given as
J1=(1/12) ×m×L^2

moment of inertia for sphere is given as
J1=(2/5) ×m×r^2

As object rotates around free end of rod then for sphere the axis around what it rotates is at a distance of d2=L+R
For rod distance is d1=0.5*L
By Steiner theorem
for the rod we get 

for the sphere we get 

And the total moment of inertia for the first case is

b) F=476 N
The torque for system is given as

where a is angle between Force and distance d
and where d represent distance from rotating axis.
In this case a = 90 degree

M=476*2.44 = 1161.44 Nm
The acceleration is calculated as

= 0.854 rad/sec^2