Ask question

Ask question

All categories

3 years ago

10

If you change the number of loops in a solenoid, what happens to the strength of the magnetic field of an electromagnet?

1 answer:

zhenek [66]3 years ago

6 0

The strength of the magnetic field is proportional to the number of turns in the solenoid; this means that the strength of the field will increase or decrease as you increase or decrease the number of turns in the coil, respectively - they are directly related.

Hope this helps!

You might be interested in

What are the SI units for distance and time?

Anton [14]

Answer:

distance is meters, time is seconds

8 0

3 years ago

Read 2 more answers

Select the correct answer. Brian is repairing an old alarm clock. He needs to replace a device that converts the electric energy

Stella [2.4K]

it shouldbe a buzzer

3 0

2 years ago

Read 2 more answers

A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the

vitfil [10]

Answer:

F₂ = -7.3 N

Explanation:

Given that,

The mass of an object, m₁ = 3.7 kg

First force, F₁ = 11 N

The net acceleration of the object is 1 m/s².

We know that,

F₁+F₂ = ma

11+F₂ = (3.7)(1)

F₂ = 3.7-11

F₂ = -7.3 N

so, the other force is 7.3 N and it is acting in west direction.

7 0

2 years ago

The driving force for an electric current is called

qaws [65]

Its called electro motive force . let me know if its right

6 0

3 years ago

Read 2 more answers

If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2

kaheart [24]

Answer:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

$Q = -kA \frac{\Delta T}{\Delta x}$ (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

$\Delta T$ is the temperature of difference that we want to find

$\Delta x=2.5 cm =0.025 m$ represent the thickness of the material

If we solve $\Delta T$ in absolute value from the equation (1) we got:

$\Delta T =\frac{Q \Delta x}{Ak}$

First we convert 3KW to W and we got:

$Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W$

And we have everything to replace and we got:

$\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K$

So then the difference of temperature across the material would be $\Delta T = 375 K$

5 0

3 years ago