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vazorg [7]
3 years ago
12

I need a story about kepler's laws for a child, something a child would understand. And i'd like it to be okay for someone if I

copy anhd paste it or else my parents are gonna kill me and my teacher will be very disappointe, this is for summer school.
Physics
2 answers:
andreyandreev [35.5K]3 years ago
8 0

Answer:

(1) The orbits are ellipses, with focal points ƒ1 and ƒ2 for the first planet and ƒ1 and ƒ3 for the second planet. The Sun is placed in focal point ƒ1.

(2) The two shaded sectors A1 and A2 have the same surface area and the time for planet 1 to cover segment A1 is equal to the time to cover segment A2.

(3) The total orbit times for planet 1 and planet 2 have a ratio a13/2 : a23/2

juin [17]3 years ago
8 0

Answer:

g the day off and I will be there at work and I will be there at work and I will

Explanation:

you are not going to be able to make it to the meeting tonight but I can tomorrow

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T5<br> ujkm,g hvjnyru6yuhtghdxz5y5esahrfghfdhfgh
Hunter-Best [27]

Answer:

me too

Explanation:

4 0
3 years ago
How much kinetic energy does a 2500kg minivan traveling at 35m/s have?
Cerrena [4.2K]

Answer:

Formular of kinteic energy is 0.5 × (mass x velocity)²

0.5 × 2500 kg × 35² =1,531,250 jules

3 0
3 years ago
La ce distanta de la suprafata Pamintului intensitatea cimpului sau gravidational este egala cu 1 N/kg ?
Ulleksa [173]
Acceleration of gravity is proportional to  1/D² .
('D' is the distance from the Earth's center.)

We need  (D / R)² = 9.8
('R' is the Earth's radius.)

D/R = √9.8 = 3.13

Distance from Earth's <u>center</u> = 3.13 R
Distance above Earth's <u>surface</u> = 2.13 R = about 13,570 km =====================================================

<span>Accelerarea de gravitate este proporțională cu 1 / D².
('D este distanța de centrul Pământului.)

Avem nevoie de (D / R) ² = 9,8
('R' este raza Pământului.)</span><span>

D / R = √9.8 = 3,13

Distanța de la <u>centrul</u> Pamantului = 3,13 R
Distanța de deasupra <u>suprafetei</u> Pamantului = 2.13 R = aproximativ <span><em>13,570 km</em></span></span>
6 0
4 years ago
What is the symbol for a change in position?<br> Ad<br> p<br> d<br> Ap
Rudiy27

change in position of an object we use the

symbol ∆×\ delta×∆×for displacement, where ∆. means

"change" ∆ vector quantity with units of distances start

text ,d,I,s,t,a,n,c,e , end text.

7 0
3 years ago
While the negatively charged rod is near the disk without touching it, a hand briefly touches the end of the post. Then the nega
Paraphin [41]

Answer:

that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

Explanation:

Let us carefully analyze the situation, when the bar is facing the index post a load of equal magnitude, but opposite sign on its surface, these two charges are in balance; When the hand touches the pole, it creates a path to the ground where the charges that were induced on the pole can be balanced with the charge coming from the ground, leaving a zero charge on the pole.

 

   Now if the hand is removed, there can be no exchange of charges with the earth. When the bar is removed, the induced loads are redistributed in the post, but the excess loads that came from the earth that have the same value and are of a sign opposite to the induced ones remain, you want to sign that they are of the same sign as the charges of the bar.

   In summary, after the process, the post has a load of equal magnitude and sign (negative) that of the bar.

   If we assume that initially the weather vane was at rest, by this load that remained on the pole it would begin to move.

4 0
3 years ago
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