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Sindrei [870]
1 year ago
5

Two birds sit at the top of two different trees 17.8 feet away from one another. the distance between the first bird and a birdw

atcher on the ground is 37.4 feet. what is the angle measure, or angle of depression, between this bird and the birdwatcher? two trees have a bird on top of each. distance between birdwatcher and first bird is 37 point 4 feet. distance between each bird is 17 point 8 feet. angle of depression between birdwatcher and first bird is unknown. © 2011 jupiter images corporation 25.5° 64.5° 28.4° 61.6°
Physics
1 answer:
Yanka [14]1 year ago
7 0

The angle of depression between the bird and the birdwatcher is 61.32°

In the question, it is said that the distance between two birds is 17.8ft and the distance between the first bird and the birdwatcher is 37.4ft. So, when we draw an image in our mind then we can say that this whole system forms a right-angle triangle with a base of 17.8ft and a hypotenuse of 37.4ft. As we know that to calculate the angle of depression we will use trigonometric equations here i.e.,

cos x = Base/Hypotenuse

cos x = 17.8 / 37.4

cos x = 0.48

x = cos⁻¹(0.48)

x =  61.32°

Thus, the angle of depression is 61.32°.

Learn more about the angle of depression here:

brainly.com/question/26154210

#SPJ4

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Complete Question

 The complete question is shown on the first uploaded image  

Answer:

The total pressure is  P_T  = 10.79*10^{5} N/m^2

The temperature at the bottom is T_b  = 284.2 \ K

Explanation:

From the question we are told that

    The length of the glass tube is  L  = 1.50 \ m

      The length of water  rise at the bottom of the lake  d = 1.33 \ m

     The depth of the lake is  h =  100 \ m

     The air temperature is T_a   =  27 ^oC =  27 +273 =  300 \ K

      The atmospheric pressure is  P_a = 1.01 *10^{5} N/m

      The density of water is \rho =  998 \ kg/m^3

The total pressure at the bottom of the lake is mathematically represented as

                 P_T  =  P_a + \rho g h

substituting values

               P_T  = 1.01*10^{5}  + 998 * 9.8 * 100

               P_T  = 10.79*10^{5} N/m^2

According to ideal gas law

         At the surface the glass tube not covered by water at surface

             P_a V_a =  nRT_a

Where is the volume of

             P_a *A * L  = nRT_a

 At the bottom of the lake  

           P_T V_b  =  nRT_b

Where V_b is the volume of the glass tube not covered by water at bottom

          and  T_b i the temperature at the bottom

  So the ratio between the temperature  at the surface to the temperature at the bottom is mathematically represented as

             \frac{T_b}{T_a}  =  \frac{d * P_T}{P_a * h}

substituting values

           \frac{T_b}{27}  =  \frac{0.133  * 10.79 *10^5}{1.01 *10^{5} * 1.5}

   =>     T_b  = 284.2 \ K

           

       

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