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avanturin [10]
3 years ago
15

Bromine vapour is heavier than air. even so it's spreads upwards in the experiment above. Why?

Physics
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

hi how are u fine thanks you

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A certain 60.0 Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 11.6 kV/m.
yuradex [85]

Explanation:

Given that,

Frequency of the power line, f = 6 Hz

Value of maximum electric field strength of 11.6 kV/m

(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :

c=f\lambda

\lambda=\dfrac{c}{f}

\lambda=\dfrac{3\times 10^8\ m/s}{60\ Hz}

\lambda=5\times 10^6\ m

(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.

(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :

B_0=\dfrac{E_0}{c}\\\\B_0=\dfrac{11.6\times 10^3}{3\times 10^8}\\\\B_0=3.86\times 10^{-5}\ T

So, the maximum magnetic field strength is 3.86\times 10^{-5}\ T.

7 0
3 years ago
Read 2 more answers
No force is necessary to
igor_vitrenko [27]
No force is necessary to keep a moving object moving (in a straight line at a constant speed).
4 0
3 years ago
What is the mass of an object if a 30 N force makes it accelerate at 6 m/s2
jasenka [17]

Answer:

5 kg

Explanation:

Acceleration = 6 m/s^2

Force = 30 N

Force = mass * acceleration

mass = force / acceleration

mass = 30 / 6

mass = 5 kg

4 0
2 years ago
If a ball rolls at constant velocity, it is rolling at constant speed? explain
Shtirlitz [24]
Velocity is speed with direction. So, if velocity varies directly with speed, that statement would be true. A constant velocity would resort in a constant speed. They are connected and are dependant on each other.

I hope this helps!
~kaikers
7 0
3 years ago
If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?
Mariana [72]

The kinetic energy of the phone right before it hits the ground is 9J.

<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of the phone
  • v is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

7 0
1 year ago
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