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3 years ago

If a net force of 25 N is exerted over a distance of 4 m to the right on a 2 kg mass initially at rest and moves it, what is

Physics

1 answer:

astra-53 [7]3 years ago

6 0

Answer:

10 m/s

Explanation:

Force is mass times acceleration:

F = ma

25 N = (2 kg) a

a = 12.5 m/s²

Given:

v₀ = 0 m/s

Δx = 4 m

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (12.5 m/s²) (4 m)

v = 10 m/s

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An isotope of carbon has 6 protons and 8 neutrons.

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The answer is D. C-14.

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3 years ago

Two ranger stations are on an east-west line 110 mi apart. A forest fire is located on a bearing of N 42º E from the western sta

olchik [2.2K]

Answer:

Explanation:

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3 years ago

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Marysya12 [62]

Answer:

Transverse

Explanation:

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2 years ago

A piano wire with mass 2.60g and length 84.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and amplit

likoan [24]

Answer:

Power will be 0.2023 watt

And when amplitude is halved then power will be 0.0505 watt

Explanation:

We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg

Length of wire l = 84 cm = 0.84 m

So mass density $\mu =\frac{m}{l}=\frac{0.0026}{0.84}=0.0031kg/m$

Tension in the wire T = 25 N

Frequency f = 120 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 120=753.6rad/sec$

And amplitude A = 1.6 mm = 0.0016 m

We have to find the generated power

Power is given by $P=\frac{1}{2}\sqrt{\mu T}\omega ^2A^2=\frac{1}{2}\times \sqrt{0.0031\times 25}\times 753.6^2\times 0.0016^2=0.2023watt$

From the relation we can see that power $P\ \propto\ A^2$

So if amplitude is halved then power will be $\frac{1}{4}$ times

So power will be equal to $\frac{0.2023}{2}=0.0505watt$

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3 years ago

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