Question

8. A 2 kg flower pot weighing 20 N falls from a window ledge.

Answer 1

The force of the air resistance is 4 N.

The given parameters;

• mass of the flower pot, m = 2 kg

• weight of the flower pot, W = 20 N

Let the air resistance = F

Apply Newton's second law of motion to determine the force of the air resistance acting upward to oppose the motion of the pot falling downwards.

$\Sigma F = ma\\\\W - F = ma\\\\a = \frac{W - F}{m} \\\\8 = \frac{20 - F}{2} \\\\20 - F = 16\\\\F = 20 - 16\\\\F = 4 \ N$

Thus, the force of the air resistance is 4 N.

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