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Luden [163]
3 years ago
7

cho hệ cơ học như hình vẽ hai đầu dây buộc hai vật có khối lượng tương ứng là m1=2kg và m2>m1 lấy g=10m/s sau 1s kể từ lúc bắ

t đầu chuyển dộng hệ vật đi được 50 cm tính m2 và sức căng của dây
Physics
1 answer:
Sever21 [200]3 years ago
7 0

xin lỗi không có sơ đồ vui lòng cho biết sơ đồ



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A circular-motion addict of mass 82.0 kg rides a Ferris wheel around in a vertical circle of radius 10.0 m at a constant speed o
alisha [4.7K]

Answer:

(a) Time period is 8.85 s

(b) Normal force at the highest point is 390.2 N

(c) Normal force at the lowest point is 1217 N

Explanation:

Given:

Mass of person, m = 82.0 kg

Radius of the wheel, r = 10.0 m

Speed of the wheel, v = 7.10 m/s

(a) Time period of the circular motion is determine by the relation:

T=\frac{2\pi r}{v}

Substitute the suitable values in the above equation.

T=\frac{2\pi\times10 }{7.10}

T = 8.85 s

(b) The normal force ( F ) at the highest point of the circular path is given by the relation:

F = F₁ - F₂     ....(1)

Here F₁ is gravitational downward force acting on the person and F₂ is the centripetal force.

Gravitational Force, F₁ = mg

Here g is acceleration due to Earth's gravity.

Centripetal force, F₂ = mv²/r

Thus, the equation (1) becomes:

F=mg-\frac{mv^{2} }{r}

Substitute the suitable values in the above equation.

F=82\times9.8-\frac{82\times7.10^{2} }{10}

F = 390.2 N

(c) The normal force ( F ) at the lowest point of the circular path is given by the relation:

F = F₁ + F₂     ....(2)

Here F₁ is gravitational downward force acting on the person and F₂ is the centripetal force.

Thus the equation (2) becomes:

F=mg+\frac{mv^{2} }{r}

F=82\times9.8+\frac{82\times7.10^{2} }{10}

F = 1217 N

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3 years ago
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Answer:

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Required

acceleration a

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v=u+at

substitute our given data

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15=0.3a

divide both sides by 0.3

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Answer:

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