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forsale [732]
3 years ago
14

I need the answers to this please

Physics
1 answer:
SpyIntel [72]3 years ago
4 0

this was posted on accident i'm so sorry ahh

Answer:

Explanation:              

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A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a g
Gre4nikov [31]

Answer:

<h3>After 3seconds</h3>

Explanation:

A supersonic aircraft flies at 3 km altitude at a speed of 1000 m/s on a standard day. How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer

Using the formula for calculating speed expressed as;

Speed = Distance/Time

Given;

Distance = 3km = 3000m

Speed = 1000m/s

Required

How long after passing directly above a ground observer is the sound of the aircraft heard by the ground observer (Time)

From the formula;

Time = Distance/speed

Time = 3000/1000

Time = 3seconds

Hence the sound of the aircraft is heard after 3 seconds

7 0
3 years ago
Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe
goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

\lambda=\dfrac{h}{\sqrt{2mE}}

Therefore , E=\dfrac{h^2}{2 \lambda^2 m}

It is given that both electron and proton have same wavelength.

Therefore,

E_e=\dfrac{h^2}{2 \lambda^2 m_e}   .... equation 1.

E_p=\dfrac{h^2}{2 \lambda^2 m_p}   .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}

Putting value of mass of electron = 9.1\times 10^{-31}\ kg and mass of proton = 1.67\times 10^{-27}\ kg.

We get :

\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16

Hence , this is the required solution.

4 0
4 years ago
Read 2 more answers
A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?
Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

5 0
3 years ago
A fission reaction is one in which the weaker electrostatic repulsion force wins out over the ___________ nuclear force and, as
natulia [17]
The answer is b. Strong

6 0
4 years ago
Read 2 more answers
Which of the following requirements must be present to hear a sonic boom?
Lorico [155]

Answer:

D) The velocity of the airplane must be greater than the speed of sound

Explanation:

Sonic boom is a phenomenon that occurs when an airplane travels ay a velocity greater than the speed of sound.

When this condition is met, the sound waves produced by the airplane (mainly from the engine) is not able to travel ahead of the plane, because the plane is moving at a greater speed than the sound itself; as a result, it is only transmitted behind the plane.

In this situation, a shock wave is produced. This shock wave is associated with a very loud "bang", that can be heard clearly even at several kilometers distance (in fact, supersonic planes are normally not allowed to fly over residential areas. In the past, for example the Concorde, was only allowerd to fly at supersonic speed over the ocean).

So the correct answer is

D) The velocity of the airplane must be greater than the speed of sound

6 0
3 years ago
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